She<span> is </span>going<span> to </span>pour<span> it </span>into<span> a </span>paint tray<span> that </span>measures 10 inches wide<span>, </span>12 inches long, and5 cm deep. (1 gallon<span> =... ... (</span>1 gallon<span> = </span>231 in3<span>, </span>1 inch<span> = </span>2.54 cm<span>) Which of the </span>following scenarios will<span>happen? a. The </span>paint will<span> not fill it
</span>
Answer:
height ≈ 31 ft
Step-by-step explanation:
The illustration below will form a right angle triangle. He is standing 17 ft away from the base of the statue. The angle of elevation from the ground to the top of the statue is 61°. The height of the statue can be computed below.
adjacent side of the triangle = 17 ft
opposite side = a
Using SOHCAHTOA principle
tan 61° = opposite/adjacent
tan 61° = a/17
cross multiply
a = 17 tan 61°
a = 17 × 1.80404775527
a = 30.6688118396
a ≈ 31 ft
Turn 14 into 16, 4 x 4 = 16, 4 x 8 = 32, 32 x 4 = 128cm
Answer:
7
Step-by-step explanation:
So lets get to the problem
<span>165°= 135° +30° </span>
<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>
<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>
<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>
<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>
<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
