Volume of a cone = (π.R²)(h/3)
Diameter = 14cm then R=7 cm
Height = h= 2cm
Hence V=*π.7²)(2/3) ==> 98π/3 or 102.625 cm³
Answer:
Step-by-step explanation:
Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer:C
Step-by-step explanation:
The answer is C because the minimum is 33 and the maximum is 51. The first quartile is 33. THE SECOND QUATILE IS 39 and the 3rd quartile is 47.
Answer:
your answer is B uwu have good day
Step-by-step explanation:
