A and b can do a piece of work in 12 days. If a alone have to finish the job among b and c so
A and b=12
A (24 days alone without b)
So if b and c 15 days and c 20 days. If a have to do all I would add 24 and 15 and 20 which would be 59 days
Answer:
0
Step-by-step explanation:
-(-x) ^3-x^3
x^3-x^3
=0
Answer:
Step-by-step explanation:
Answer:
3x-4
Step-by-step explanation:
Hope this helps!
Answer:
1. 18
2. 6
3. ?
4. 3
5. 4
6. 1
7. 5
Step-by-step explanation:
1. 6 x 3 = 18
2. 2 + 4 = 6
3. ( I cant read the problem)
4. 6 - 3 = 3
5. 2 x 2 = 4
6. 3 ÷ 3 = 1
7. 6 - 1 = 5
8. 6 + 2 = 8
