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Alex787 [66]
3 years ago
5

I WILL GIVE BRAINLIEST Solve for x Answer must be simplified

" id="TexFormula1" title="\frac{x}{7}" alt="\frac{x}{7}" align="absmiddle" class="latex-formula"> ≥ -6
Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

x ≥ -42

Step-by-step explanation:

x/7 ≥ -6

Multiply each side by 7

x/7 *7  ≥ -6 *7

x ≥ -42

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Ad libitum [116K]

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5 0
2 years ago
Can someone please explain how to do these?
Pani-rosa [81]

Answer:

<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5


Step-by-step explanation:

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So we have:

9x-3\\9(8)-3\\72-3\\69

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For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value x=1 into the simplified expression to get the correct answer. Shown below:

\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}

<em>Now putting 1 in x gives us the limit:</em>

\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5

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3 0
3 years ago
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