Question

When a coordinate grid is superimposed on a map of lanesville the middle school is located at (15,13) and the librart is located at (27,9). If each unit represents 1 mile how many miles apart are the middle school in the liebrary round your answer to the nearest 10th

Answer 1

Answer:

4.5 miles

Step-by-step explanation:

Given

$Middle\ School = (15,13)$

$Library = (27,9)$

To solve this, we simply solve for the distance (D) between both points.

$D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Where:

$(x_1,y_1) = (15,13)$

$(x_2,y_2) = (27,9)$

$D = \sqrt{(27 - 25)^2 + (9 - 13)^2}$

$D = \sqrt{(2)^2 + (-4)^2}$

$D = \sqrt{4 + 16}$

$D = \sqrt{20}$

$D=4.472135955$

$D=4.5$ --- approximated

Since each unit is 1 mile. The distance is 4.5 miles