Answer:
![s=t-18...(1)](https://tex.z-dn.net/?f=s%3Dt-18...%281%29)
![12*s=10*t+32...(2)](https://tex.z-dn.net/?f=12%2As%3D10%2At%2B32...%282%29)
Step-by-step explanation:
Let s be the number of pages in each issue of the sports magazine, and t be the number of pages in each issue of the technology magazine.
We have been given that Each issue of the sports magazine has 18 fewer pages than each issue of the technology magazine. We can represent this information in an equation as:
![s=t-18...(1)](https://tex.z-dn.net/?f=s%3Dt-18...%281%29)
We are also given that sports magazine prints 12 issues per year, so the total number of pages in all the issues of sports magazine will be 12*s.
We are given that a technology magazine prints 10 issues per year, so the total number of pages in all the issues of technology magazine will be 10*s.
Further, the total number of pages in all the issues of the sports magazine for one year is 32 more than the total number of pages in all the issues of the technology magazine for one year.
We can represent this information in an equation as:
![12*s=10*t+32...(2)](https://tex.z-dn.net/?f=12%2As%3D10%2At%2B32...%282%29)
Therefore, our desired system of equations will be:
![s=t-18...(1)](https://tex.z-dn.net/?f=s%3Dt-18...%281%29)
![12*s=10*t+32...(2)](https://tex.z-dn.net/?f=12%2As%3D10%2At%2B32...%282%29)
Requied equation is (x - 0)^2 = 4p(y - 0)
x^2 = 4py
But 0 + p = 0.75 => p = 0.75
Therefore, equation is x^2 = 4(0.75)y
x^2 = 3y
y = 1/3 x^2
Answer:
<em>The answer is 156cm^2</em>
Step-by-step explanation:
<em>Solution:</em>
<em>The shape given is a trapezium.</em>
<em>The area of the green region = Area of the outer trapezium - Area of the inner trapezium.</em>
<em></em>![Area\: of\:a\:trapezium\:=\frac{1}{2}\:(a+b)h](https://tex.z-dn.net/?f=Area%5C%3A%20of%5C%3Aa%5C%3Atrapezium%5C%3A%3D%5Cfrac%7B1%7D%7B2%7D%5C%3A%28a%2Bb%29h)
![Where\: a,b\:are\:the\:bases,\:h=height](https://tex.z-dn.net/?f=Where%5C%3A%20a%2Cb%5C%3Aare%5C%3Athe%5C%3Abases%2C%5C%3Ah%3Dheight)
![For,\:outer\:trapezium,](https://tex.z-dn.net/?f=For%2C%5C%3Aouter%5C%3Atrapezium%2C)
![a=10cm,\:b=14cm,h=16cm](https://tex.z-dn.net/?f=a%3D10cm%2C%5C%3Ab%3D14cm%2Ch%3D16cm)
![Area\:of\:the\:outer\:trapezium=\frac{1}{2}\:(10+14)16](https://tex.z-dn.net/?f=Area%5C%3Aof%5C%3Athe%5C%3Aouter%5C%3Atrapezium%3D%5Cfrac%7B1%7D%7B2%7D%5C%3A%2810%2B14%2916)
![=\frac{1}{2}(24)(16)=192cm^{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%2824%29%2816%29%3D192cm%5E%7B2%7D)
![For\:inner\:trapezium,](https://tex.z-dn.net/?f=For%5C%3Ainner%5C%3Atrapezium%2C)
![a=3cm,b=6cm,h=8cm](https://tex.z-dn.net/?f=a%3D3cm%2Cb%3D6cm%2Ch%3D8cm)
![Area\:of\:the\:inner\:trapezium=\frac{1}{2}(3+6)8](https://tex.z-dn.net/?f=Area%5C%3Aof%5C%3Athe%5C%3Ainner%5C%3Atrapezium%3D%5Cfrac%7B1%7D%7B2%7D%283%2B6%298)
![=\frac{1}{2}(9)(8)=36cm^{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%289%29%288%29%3D36cm%5E%7B2%7D)
![193cm^{2}-36cm^{2}](https://tex.z-dn.net/?f=193cm%5E%7B2%7D-36cm%5E%7B2%7D)
![=156cm^{2}](https://tex.z-dn.net/?f=%3D156cm%5E%7B2%7D)
<em>The answer is 156cm^2</em>
<em></em>
<em></em>
Thirty two and one hundred six thousandths.
Answer:
she will earn 300.3 in interest
Step-by-step explanation:
using the formula for interest: I =Prt where P is the principal (starting amount), r is the rate, and t is the time. Always convert the rate to a decimal if it's in percentage form.
I = (3850)(0.013)(6)