In this case it is to find the roots of the polynomial.
We have then:
2x ^ 2-5x + 1 = 3
Rewriting:
2x ^ 2-5x-2 = 0
Applying resolver we have
x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
Substituting values:
x = (- (- 5) +/- root ((- 5) ^ 2 - 4 (2) (- 2))) / (2 (2))
x = (- (- 5) +/- root ((25 + 16)) / (2 (2))
x = (5 +/- root (41))) / (4)
x = ((5/4) +/- (root (41)) / 4)
Answer:
x = ((5/4) +/- (root (41)) / 4)
(option 4)
Answer:
(2, 3).
Step-by-step explanation:
3x+2y=12
6x+3y=21 Multiply the first equation by 3 and the second by 2:
9x + 6y = 36
12x + 6y = 42 Subtract:
-3x = -6
x = -6/-3 = 2.
Plug x = 2 into the first equation:
3(2) + 2y = 12
2y = 12 - 3(2)
2y = 6
y = 3.
Answer:
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