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DaniilM [7]
3 years ago
8

-x-7" alt="y=-\frac{3}{5} x-5\\y=-x-7" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
7 0

Answer:

Step-by-step explanation:

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Jaz has the following scores from a new game:
DENIUS [597]
The outlier is 84 and if you removed the outlier from the mean it would decrease.
6 0
2 years ago
Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG
qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

  1. Opposite sides are equal and parallel.
  2. Opposite angles are equal to each other.
  3. Consecutive angles are supplementary
  4. The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

5 0
3 years ago
Prove that: √(sec x + 1)/(sec x - 1) = 1/(cosec x - cot x) ​
Anastasy [175]

Answer:

Sorry Bro

Step-by-step explanation:

I don't know the ans plzz donnot mind

5 0
2 years ago
Read 2 more answers
The work of a student to solve the equation 2(5y − 2) = 12 + 6y is shown below:
jolli1 [7]
We know that Step 1 is correct, because it is just a restatement of the equation. Therefore, we can eliminate Step 1:

2(5y – 2) = 12 + 6y

In Step 2, the student tried using the Distributive Property. The Distributive Property can be written as one of the two following formulas:

a(b + c) = ab + ac
a(b – c) = ab – ac

In this case, we'll use the second formula. Substitute any known values into the equation above and simplify:

2(5y – 2) = 2(5y) – 2(2)
2(5y – 2) = 10y – 4

In Step 2, the student calculated 2(5y – 2) to equal 7y – 4. However, we have just proven that 2(5y – 2) is equal to 10y – 4.

The student first made an error in Step 2, and the correct step is:

Step 2: 10y – 4 = 12 + 6y

I hope this helps!
8 0
3 years ago
The domain of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is
LUCKY_DIMON [66]
Given:
  3, -2
  1,  2
-1, -4
-1,  2

The format is (x,y)

The domain is all the x-values while range is all the y-values.

domain: (3,1, -1,-1) 2nd option given.

4 0
4 years ago
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