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3 years ago

I need help ASAP!!!Please explain you answer

Mathematics

1 answer:

just olya [345]3 years ago

5 0

Answer:

Step-by-step explanation:

The body of the Cylinder.

Formula

Area of the body = circumference * length

circumference = 2*pi * r

r = 6 m

Circumference = 2 * 3.14 * 6

Circumference = 12 * pi

Area of body = 12*pi * length

area of body = 12*9 * pi

Area of body = 108* pi

Two ends

The diagram is not complete enough to know whether or not there are 2 ends or one. I'll assume 2.

Area = 2 * pi r^2 For both

Area = 2 * pi * 6^2

Area = 72 pi

Total Area

Total area = 72 pi +108 pi

Total area = 180 pi

Total Area = 180 * 3.14

Total Area = 565.2

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What is the surface area of a square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall

scZoUnD [109]

Answer:

115 in²

Step-by-step explanation:

SA = Area of triangular surfaces + area of the square base

SA= 2bh + b²

SA = 2(5)(9)+5²

SA = 90+25

SA = 115

7 0

3 years ago

Solve for x: 1/2x - 4 = 8

iris [78.8K]

First do 8 + 4 which is 12

Next do 12 times 2 which is 24

Final step is to do 24 divided by 1 which gets you 24

The answer is 24.

5 0

3 years ago

What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?

german

For this case we have the following function:
$f(x) = tan(\frac{x^2}{9})$
The average rate of change is given by:
$AVR = \frac{f(x2) - f(x1)}{x2- x1}$
Evaluating the function for the given interval we have:
For x = 1.25:
$f(1.25) = tan(\frac{1.25^2}{9})$
$f(1.25) = 0.18$
For x = 2:
$f(2) = tan(\frac{2^2}{9})$
$f(2) = 0.48$
Then, replacing values we have:
$AVR = \frac{0.48 - 0.18}{2 - 1.25}$
$AVR = 0.4$
Answer:
the average value of on the closed interval [1.25, 2] is:
$AVR = 0.4$

3 0

3 years ago

A random sample of the amounts for 22 purchases was taken. The mean was $42.97, the standard deviation was $22.82, and the m

Illusion [34]

Answer: a) 84 and b ) 2084

Step-by-step explanation:

Given : Sample standard deviation : s= $22.82

(Population standard deviation is unknown ) , so we use t-test.

Critical value or the 95% confidence intervals : $t_{n-1}*=2.0$