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musickatia [10]
4 years ago
6

The line-emission spectrum of an atom is caused by the energies released when electrons

Physics
1 answer:
Paul [167]4 years ago
4 0

Answer:

makes a transition from a high to a lower energy state

Explanation:

The emission spectrum is the spectrum of electromagnetic radiation emitted due to the transition from a state of high energy to a state of lower energy made by an electron in the atoms of the chemical element or compound. The emitted photons have an energy equal to the difference in energy between the two states.

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At what temperature is the average kinetic energy of an atom in helium gas equal to 6.21 x 10-21 j?
NARA [144]

The average kinetic energy of an atom in helium gas at temperature T is given by,

K.E=\frac{3}{2}KT

here, K is botzmann constant =1.38×10⁻²³ m² kg s⁻² K⁻¹

Given, K.E= 6.21×10⁻²¹ J

Substituting the values,

6.21*10^{-21}=\frac{3}{2}1.38*10^{-23}T

T= 300 K

Therefore, at temperature 300 K the average kinetic energy of the atom in helium gas is 6.21×10⁻²¹ J.

5 0
4 years ago
Gravity affects atmospheric pressure true or false
Burka [1]

Answer:

false

Explanation:

5 0
3 years ago
Cells are visualized using light microscopes and electron microscopes. Which statement about microscopes is false. Group of answ
denpristay [2]

Answer:

Light microscopes use light and glass objectives to illuminate and magnify objects

Explanation:

Light microscopes and electron microscopes are used to study cells. The electron microscope has many times more resolving power than the ordinary light microscope. A light microscope contains an objective lens and an eyepiece through which the final image is seen.

Both light and electron microscopes magnifies the image of the object. The magnifying power of an electron microscope is many times that of the light microscope.

4 0
3 years ago
If a rock climber accidentally drops a 77.5-g piton from a height of 215 meters, what would its speed be just before striking th
Viktor [21]

Let us list out what we know from the question.

Initial Velocity V_{i}  = 0 since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity a = 9.8 m/s^{2}

Final Velocity V_{f} = ?

Using the equation, V^{2} _{f} = V^{2} _{i}  + 2aD and plugging in the known values, we get

V^{2} _{f}  = 0^{2}  + 2(9.8)(215)

Simplifying by taking square-root on both sides gives us V_{f} =  64.915 m/s

Thus, the speed of the piton just before striking the ground is 65 m/s.

4 0
3 years ago
A 60 kg student is standing atop a spring in an elevator that is accelerating upward at 3.0 m/s2. The spring constant is 2.5 x 1
dimaraw [331]

the spring will be compressed by 0.3072 m

Explanation:

acceleration of elevator=3 m/s²

mass of student= 60 Kg

spring constant=2.5 x 10³ N/m

the force on the student is given by F = m ( g +a)

F=60 (9.8+3)

F=768 N

now the formula for spring force is given by

F= k x

768= 2.5 x 10³ (x)

x=0.3072 m

6 0
3 years ago
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