Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Mechanical or Electromagnetic
Answer:
a) 35.44 mm
b) 17.67 mm
Explanation:
u = Object distance = 3.6 m
v = Image distance
f = Focal length = 35 mm
= Object height = 1.8 m
a) Lens Equation
The CCD sensor is 35.34 mm from the lens
b) Magnification
The person appears 17.67 mm tall on the sensor
Answer:
A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N
Explanation:
The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object
Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object
The weight of the object on the surface of a planet = m × g
Where;
m = The mass of the object
g = The strength of gravity on the planet's surface in N/kg
The given parameters are;
The mass of the person standing on a platform at the surface of Saturn, m = 60 kg
The strength of gravity on the surface of Saturn = 9 N/kg
Therefore, we have;
The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N
Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.
