Answer:
-414.96 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
The force the ground exerts on the parachutist is -414.96 N
If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase
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Answer:
This is because motion is intended to occur but at zero acceleration. It means at a constant velocity, henceFor that to happen the pulling force F must exactly equal the frictional force Fk .
The electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.
<h3>
Electric potential energy</h3>
When work is done on a positive test charge to move it from one location to another, potential energy increases and electric potential increases.
The electric potential energy between the charges when the second charge is at point b is calculated as follows;
ΔU = -w
Ui - Uf = w
Uf = Ui - w
where;
Uf is the final potential energy
Ui is the initial potential energy
w is the work done by the force
Uf = 5.4 x 10⁻⁸ J - (-1.9 x 10⁻⁸J)
Uf = 5.4 x 10⁻⁸ J + 1.9 x 10⁻⁸ J
Uf = 7.3 x 10⁻⁸ J
Thus, the electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.
Learn more about electric potential energy here: brainly.com/question/14306881
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Answer:
Explanation:
Given that,
Mass per unit length is
μ = 4.87g/cm
μ=4.87g/cm × 1kg/1000g × 100cm/m
μ = 0.487kg/m
Tension
τ = 16.7N
Amplitude
A = 0.101mm
Frequency
f = 71 Hz
The wave is traveling in the negative direction
Given the wave form
y(x,t) = ym• Sin(kx + ωt)
A. Find ym?
ym is the amplitude of the waveform and it is given as
ym = A = 0.101mm
ym = 0.101mm
B. Find k?
k is the wavenumber and it can be determined using
k = 2π / λ
Then, we need to calculate the wavelength λ using
V = fλ
Then, λ = V/f
We have the frequency but we don't have the velocity, then we need to calculate the velocity using
v = √(τ/μ)
v = √(16.7/0.487)
v = 34.29
v = 5.86 m/s
Then, we can know the wavelength
λ = V/f = 5.86 / 71
λ = 0.0825 m
So, we can know the wavenumber
k = 2π/λ
k = 2π / 0.0825
k = 76.18 rad/m
C. Find ω?
This is the angular frequency and it can be determined using
ω = 2πf
ω = 2π × 71
ω = +446.11 rad/s
D. The angular frequency is positive (+) because the direction of propagation of wave is in the negative direction of x
