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Svetradugi [14.3K]
4 years ago
13

two lighthouses spot a boat. lighthouse A spots the boat at 55 degrees north of east is 68 meters from the boat. lighthouse B sp

ots the boat at 44 degrees north of west. which lighthouse is closer to the boat?

Mathematics
1 answer:
hodyreva [135]4 years ago
4 0

The answer & explanation for this question is given in the attachment below.

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Help please very much
Norma-Jean [14]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
Jojo likes to paint She estimates the number of paintings she completes using the function P(W) = w – 2. where w is the number o
KATRIN_1 [288]

Answer:

P[J(y)] = 2/3 * J(y) -2

Step-by-step explanation:

4 0
3 years ago
1. If the length of a rectangle is 6 more than its width, and its perimeter is 48
Salsk061 [2.6K]

For this case we have that by definition, the perimeter of the rectangle is given by:

P = 2w + 2L

Where:

W: Is the width of the rectangle

L: is the length of the rectangle

According to the data we have:

L = 6 + w\\P = 48

Substituting:

48 = 2w + 2 (6 + w)\\48 = 2w + 12 + 2w\\48 = 4w + 12\\48-12 = 4w\\36 = 4w\\w = \frac {36} {4}\\w = 9

So, the width of the rectangle is 9 inches

L = 6 + 9 = 15

So, the length of the rectangle is 15 inches

Answer:

the width of the rectangle is 9 inches

the length of the rectangle is 15 inches

5 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
jen uses 8.2 of blue paint and white paint to paint her bedroom walls. 4/5ths of this amount is blue paint, and the rest is whit
lara31 [8.8K]

Answer:

The amount of white paint Jen used to paint the walls in her room is:

  • <u>1.64 pints.</u>

Step-by-step explanation:

To solve the exercise you only have to pay attention to the statement, in the section that says that 4/5 parts of the total painting is blue, therefore, if 1 is the total painting, you must do a subtraction:

  • 1 - 4/5 = 1/5

Since the remaining white paint is 1/5 of the total, you have two ways to solve the exercise: multiply the total paint (8.2 pints) by 1/5 or divide the number by 5, as shown below:

  • <u>Amount of white paint = 8.2 pints * (1/5) = 1.64 pints. </u>
  • <u>Amount of white paint = 8.2 pints / 5 = 1.64 pints. </u>

As you can see, the two methods provide a <u>value of 1.64 pints, which corresponds to 1/5 of the total paint and is the amount of white paint used</u>.

5 0
3 years ago
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