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3 years ago

11

Which statement best describes the relationship between ABC and EDC?

1 answer:

sattari [20]3 years ago

8 0

The first one
mecayse m3 is equal to

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A quadratic equation of the form 0 = ax2 + bx + c has a discriminant value of –16. How many real number solutions does the equat

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$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{a}x^2\stackrel{\stackrel{b}{\downarrow }}{+b}x\stackrel{\stackrel{c}{\downarrow }}{+c} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ \stackrel{-16}{negative}&\textit{no solution}~~\checkmark \end{cases}$

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3 years ago

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If there are 2 numbers outside the parentheses in the distributive property which one do u distribute

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3 years ago

Simplify x+2x –8+3x+1 –2x.

emmainna [20.7K]

Answer:

4x - 7

Step-by-step explanation:

x + 2x + 3x - 2x = 4x

-8 + 1 = -7

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3 years ago

What's the square root of 15 divided by 5 square root of 20?

Arturiano [62]

Answer:

√3/10 = 0.1732

Step-by-step explanation:

√15 / 5√20 = (√5 x √3) / 5(√5 x √4) = √3 / (5 x√4) = √3 / 10

7 0

3 years ago

Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.

Sedaia [141]

Answer:

Equations with one solution: $-2(x-3) = 2x-6$

Equations with no solution:

$6(x+5) = 6x+11\\5(x-2) = 5x-7$

Equations with infinite many solutions: $-3(x-4) = -3x+12$

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

<u>Equation 1:</u>

5(x-2) = 5x-7

$5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3$

As both sides are not equal, equation has no solution.

<u>Equation 2:</u>

$-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\$

As both sides are equal the equation has infinite many solutions.

<u>Equation 3:</u>

$-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3$

As x=3, the equation has only one solution.

<u>Equation 4:</u>

$6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11$

The equation has no solution.

Hence,

Equations with one solution: $-2(x-3) = 2x-6$

Equations with no solution:

$6(x+5) = 6x+11\\5(x-2) = 5x-7$

Equations with infinite many solutions: $-3(x-4) = -3x+12$

6 0

2 years ago