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SVETLANKA909090 [29]

2 years ago

15

A music concert has 700 people attend it. Of the 700, 8% of the people arrived late and 12% of the people buy a t-shirt. How man

y people arrived late

1 answer:

Sergio039 [100]2 years ago

7 0

Answer:

56 people are late, 6 people that are late buy shirts, 644 people are on time

Step-by-step explanation:

You might be interested in

Which of the following statements are true regarding functions?

butalik [34]

Answer:

D

Step-by-step explanation:

The vertical line test, can be done with a pencil, and it's very simple. You run the object in a vertical position, horizontally across the graph, and if it hits two points on the same Y-Axis, your function is actually a relation, since functions are not allowed to have two coordinates on the same line.

7 0

2 years ago

audrey has 32 dimes and quarters in her piggy bank with a total value of $6.50. how many of the coins are dimes and how many are

AfilCa [17]

22 quarters= $5.50
10 dimes= $1.00

$5.50 + $1.00 = $6.50
I just did trial and error. I started with 20 quarters and made changes until it worked.

4 0

2 years ago

2+1.25f=10−2.75f solve for f

Inga [223]

Hey there!

2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.

1.25f + 2.75f = 4f

4f + 2 = 10
Subtract 2 from both sides.

4f = 8
Divide both sides by 4 to solve for f.

f = 2

I hope this helps!

6 0

2 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

2 years ago

Can someone help plz

KIM [24]

I think the answer is B.

8 0

2 years ago