Answer: 26 pieces of $1 bill and 34 pieces of $5 bill
Total Deposit = $196
Total Bills = 60 pieces
Value of $1 = $1
Value of $5 = $5
Lets assume all the 60 pieces were $1 bill.
The total deposit will be 60 x $1 = $60
But we know that the total deposit is $196. So the extra value must have come from the $5.
$196 - $60 = $136
There is still an outstanding amount of $136 not accounted for.
$5 - $1 = $4
The difference in the two bills is $4
Now we can find out the number of $5 bill by dividing the extra $136 by 4:
136 ÷ 4 = 34 pieces
There are 34 pieces of $5 bill.
Since there are 34 pieces of $5, the rest must be the $1 bill
60 - 34 = 26
There are 26 pieces of $1 bill.
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Answer: 26 pieces of $1 bill and 34 pieces of $5 bill.
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Answer:
81/5
Step-by-step explanation:
See image.
I always think drawing these out helps.
I had to find lower limit for x by finding when 1/x^2=4
x^2=1/4
This implies x=1/2 since in the picture x is positive.
We need to evaluate
Integral( 4 - 1/x^2 , from x=1/2 to x=5)
Or
Integral( 4 - x^-2 , from x=1/2 to x=5)
=4x+x^-1 ] from x=1/2 to x=5
(4×5+5^-1)-(4×1/2+(1/2)^-1)
(20+1/5)-(2+2)
20-(2+2)+1/5
20-4+1/5
16+1/5
81/5
