Question

The ratio of the current ages of two RSM summer camp students Dylan and Mike is 3:4. If Dylan had been 6 years younger and Mike 6 years older, the age of Mike would have been 6 times the age of Dylan. Arrange the ratios of Dylan's current age to Mike's current age, their ages in four years from now and those 4 years ago, in descending order.

Answer 1

Answer:

13:16, 3:4, 5:8.

Step-by-step explanation:

The ratio of the current ages of two students Dylan and Mike is 3:4.

Let their ages are 3x and 4x respectively.

If Dylan had been 6 years younger and Mike 6 years older, the age of Mike would have been 6 times the age of Dylan.

Hence, we can write, 6(3x - 6) = (4x + 6)

⇒ 18x - 4x = 36 + 6

⇒14x = 42

⇒ x = 3

Therefore, the current age of Dylan is 3×3 =9 years and that of Mike is 3×4 =12 years.

Therefore, the ratio of Dylan's current age to Mike's current age is 3:4. The ratio of their ages in four years ago will be (9-4):(12-4) =5:8

The ratio of their ages in four years from now will be (9+4):(12+4) =13:16

Hence, the ratios in descending order is 13:16, 3:4, 5:8.

(Answer)