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Triss [41]
4 years ago
14

What is 4(e+7)+9e+5f-11

Mathematics
2 answers:
igomit [66]4 years ago
8 0

Answer:

=5f+52.337664

Step-by-step explanation:

Irina18 [472]4 years ago
6 0

Answer:

13e+9+9f

Step-by-step explanation:

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Kenedy shares 2 oranges equally with two friends how much of an orange does each friend get
Norma-Jean [14]
1 orange. Cuz 2 divided by 2 is 1
7 0
3 years ago
Karl’s and eddie’s ages added together are equal to 65. 10 years ago, Karl was twice as old as Eddie. How old are they now
trapecia [35]

9514 1404 393

Answer:

  • Karl is 40
  • Eddie is 25

Step-by-step explanation:

10 years ago, the sum of their ages was 65 -2·10 = 45.

If Karl was twice as old as Eddie, his contribution was 2/3 of the sum and Eddie's was 1/3. That is, Karl was (2/3)(45) = 30 and Eddie was 15 at that time.

Now, Karl is 40 and Eddie is 25.

__

This can be solved using a system of equations.

  e = 65 -k

  (k -10) = 2(e -10)

Substituting the first equation into the second gives ...

  k -10 = 2((65 -k) -10)

  k -10 = 110 -2k . . . . . . . simplify

  3k = 120 . . . . . . . . . . . . add 10+2k

  k = 40

  e = 65 -40 = 25

7 0
3 years ago
What’s 6 divided by 3/5
Gala2k [10]

Answer:

The answer to the question provided is 10.

4 0
3 years ago
For a large supermarket chain in a particularâ state, aâ women's group claimed that female employees were passed over for manage
PolarNik [594]

Answer:

1) As the P-value (0.097) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the women's claim that female employees were passed over for management training in favor of their male colleagues.

2) The 95% confidence interval for the population proportion is (0.173, 0.427).

The populations proportion (π=0.4) is included in this confidence interval, so the claim has no enough evidence to be supported.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that female employees were passed over for management training in favor of their male colleagues.

We use the women's part for sample and population proportions.

Then, the null and alternative hypothesis are:

H_0: \pi=0.4\\\\H_a:\pi

The significance level is 0.05.

The sample has a size n=50 persons.

The sample proportion is p=0.3.

p=X/n=15/50=0.3

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.4*0.6}{50}}\\\\\\ \sigma_p=\sqrt{0.0048}=0.069

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.3-0.4+0.5/50}{0.069}=\dfrac{-0.09}{0.069}=-1.299

This test is a left-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z

As the P-value (0.097) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that female employees were passed over for management training in favor of their male colleagues.

b) We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.3.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.3*0.7}{50}}\\\\\\ \sigma_p=\sqrt{0.0042}=0.0648

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0648=0.127

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.3-0.127=0.173\\\\UL=p+z \cdot \sigma_p = 0.3+0.127=0.427

The 95% confidence interval for the population proportion is (0.173, 0.427).

The populations proportion (π=0.4) is included in this confidence interval, so the claim has no enough evidence to be supported.

5 0
3 years ago
Please help I will give brainiest
attashe74 [19]

Answer:

35

Step-by-step explanation:

55 + x = 90

x = 90 - 55

x = 35

6 0
3 years ago
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