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Natasha_Volkova [10]
3 years ago
14

Solve the following equation: a) 3x - 9 = 27/ 1 - 5x b) 10x - 1/x = 3

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

A) x=9/2 B) x=-1/5, 1/2

Step-by-step explanation:

3x-9=27/1-5x

3x-9=27-5x

3x-(-5x)-9=27

3x+5x-9=27

8x-9=27

8x=27+9

8x=36

x=36/8

simplify

x=9/2

Answer: x=9/2

-----------------------------

10x-1/x=3

(10x^2-1)/x=3

10x^2-1=3*x

10x^2-1=3x

10x^2-3x-1=0

factor out the trinomial,

find two numbers that when they multiply,

you get the third term, which is -1 in this case.

When you add those 2 numbers, you get the second term,

which is -3 in this case.

(5x+1)(2x-1)=0

apply the zero property from here,

set 5x+1=0 and 2x-1=0 and solve for x.

5x=0-1=-1, x=-1/5,

2x=0+1=1, 2x=1, x=1/2.

So x=-1/5, 1/2.

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Hey there! :)

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(2, -2)

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Determine the equations of the vertical and horizontal asymptotes if any for f(x)=x/x-5
Gelneren [198K]

Answer:

Horizontal Asymptote: x = 0

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Step-by-step explanation:

The function is given as  f(x)=\frac{x}{x-5}

<em>Horizontal asymptotes are found by equating numerator to 0 and solving for x</em>

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<em />

<u>Horizontal Asymptote:</u>

x = 0

<u>Vertical Asymptote:</u>

x - 5 = 0

x = 5

5 0
3 years ago
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