Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line p is
y = x - 1
Comparing with the slope intercept form, slope = 1
If two lines are parallel, it means that they have the same slope. Therefore, the slope of line q passing through (- 2, 8) is 1
To determine the y intercept, we would substitute m = 1, x = - 2 and
y = 8 into y = mx + c. It becomes
8 = 1 × - 2 + c
8 = - 2 + c
c = 8 + 2 = 10
The equation becomes
y = x + 10
Answer:
A
Step-by-step explanation:
variable
Step-by-step explanation:
Answer:
3x-2y-1=0
or, 3x-2y=1
or, x=(1+2y)/3...(i)
4x+y=27... ...(ii)
solving (i) and (ii)
(4+8y)+3y=27x3
4+11y= 81
11y=77
y=7
now,
x=(1+2x7)/3
x=5
hence, the passing point is (5,7)
now, for the radius of circle
radius of circle= distance betn (5,7) and (2,3)
r= √(5-2)²+(7-3)²
r=5units
finally,
the eqn of circle
(x-h)²+(y-k)²=r² (where (h,k)=(2,3) )
(x-2)²+ (y-3)²=5²
x²-4x+4+y²-6y+9=25
x²+y²-4x-6y=12....this is the required answer.
Answer:
Quadratic equations are similar to exponential equations by having a curve in the graph. Algebraically, linear functions are polynomial functions with a highest exponent of one, exponential functions have a variable in the exponent, and quadratic functions are polynomial functions with a highest exponent of two.
