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3 years ago

Double check work pls

Mathematics

1 answer:

EastWind [94]3 years ago

4 0

This is incorrect.

-4/9 belongs before -4/7

-4/9 = -0.44
-4/7 = -0.57
-3/5 = -0.60
-5/6 = -0.83

From least to greatest:

-4/9, -3/5, -4/7, -5/6 .

The Answer is:

A

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Add 7/10 + 1/6 enter your answer below as a fraction in lowest terms, using the slash(/) as the fraction bar

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Answer:

13/15

Step-by-step explanation:

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3 years ago

zheka24 [161]

Answer:

The circumference of the smaller circle is:

C = 2*pi*x/3

Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

C = 2*pi*R

where pi = 3.14...

Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

We know that:

The circumference of B is 3 times the circumference of A.

The radius of circle B is: OB = x

The radius of circle A is: OA

We want to find an expression of OA.

The circumference of circle B will be:

C(B) = 2*pi*OB = 2*pi*x

The circumference of circle A will be:

C(A) = 2*pi*OA

And we know that the circumference of circle B is 3 times the circumference of circle A, then:

C(B) = 3*C(A)

replacing the equations for the circumferences, we get:

2*pi*x = 3*(2*pi*OA)

dividing both sides by 2*pi, we get:

x = 3*OA

Now we want to solve this for OA, then we need to isolate it,

x/3 = OA

We can conclude that the radius of the smaller circle is equal to x/3.

Then the circumference of circle A is:

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5 0

3 years ago

Please help solve this system of equations

stepan [7]

Make a substitution:

$\begin{cases}u=2x+y\\v=2x-y\end{cases}$

Then the system becomes

$\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}$

Simplifying the equations gives

$\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}$

which is to say,

$\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}$

$\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81$

$\implies\dfrac uv=\pm27$

$\implies u=\pm27v$

Substituting this into the new system gives

$\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1$

$\implies u=\pm27$

Then

$\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13$

(meaning two solutions are (7, 13) and (-7, -13))

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3 years ago

This is a scale drawing of a field. The scale is 1 in.: 10 ft. What is the actual length of the

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Answer:7ft

Step-by-step explanation:

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3 years ago

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Let's V the speed of the girl in step
v the speed of the escalator in step
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V*60+v*60=L ==> V+v=L/60
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2V=L(3+2)/180
==>V=5L/360
Time to climb (in step) with v=0 (escalator standing still)
V*t=L==> t=L/V=L/(L*5/360)=72

The girl will count 72 steps.

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4 years ago

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