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andrew-mc [135]
3 years ago
13

HELP!!! MATH PROBABILITY QUESTION!

Mathematics
2 answers:
mafiozo [28]3 years ago
8 0

Answer:

0.375

Step-by-step explanation:

3/8 = 0.375

3 divide by 8 = 0.375

ra1l [238]3 years ago
3 0

Answer:

0.375 or if we are rounding 38%

Step-by-step explanation:

simple take 3/8=0.375

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What does it mean to analyze a graph and write a story for a function? Explain and give an example.
Evgesh-ka [11]

Answer:

Step-by-step explanation:

To analyse a graph you are meant to determine a general trend, relating the results of an experiment to the hypothesis as well as to form. For example you look at all the values in a line graph and you are yo predict one you are to find its common increase or decrease.

If all possible vertical lines will only cross the relation in one place, then the relation is a function.This works because if a vertical line crosses a relation in more than one place it means that there must be two y values corresponding to one x value in that relation.

7 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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n200080 [17]

Answer: 7/12

Step-by-step explanation:

5 0
3 years ago
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antiseptic1488 [7]

Answer:

8 mil.

Step-by-step explanation:

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3 years ago
What would y equal if you substituted 2 in y+2x=3
Ivahew [28]

Answer:

-1

Step-by-step explanation:

Given the equation:

y+2x=3

Substitute x=2 into this equation:

y+2\cdot 2=3\\ \\y+4=3

Subtract 4:

y+4-4=3-4\\ \\y=-1

8 0
3 years ago
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