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2 years ago

What is the area of the figure? Enter your answer in the box.

Mathematics

1 answer:

nordsb [41]2 years ago

6 0

Answer:

The area of the figure = 112 in²

Step-by-step explanation:

The figure consist of:

1) A square of side length of 10 in.

2) A right triangle with a base of (10 - 6 = 4 in) and a height of (16 - 10 = 6 in)

So,

The area of the square = (side length)² = 10² = 100 in²

The area of the triangle = 0.5 * height * base = 0.5 * 6 * 4 = 12 in²

So,

The total area = 100 + 12 = 112 in²

The area of the figure = 112 in²

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Sally had 1000 photos to put into a photo album.She set 10 photos aside to place in frames.If her photo album fits 3 photos per

Kruka [31]

Answer:

Sally needed 330 pages of album to place her photos in it.

Step-by-step explanation:

Given:

Total number of photos = 1000

Number of photos kept aside to be place in frame = 10

Number of photos in per page of album = 3

We need to find the number of pages needed to place the photos in album.

Solution:

First we will find the number of photos to be place in album.

Now we know that she kept aside some photos which has to be frame framed.

So number of photos to be place in album can be calculated by Subtracting Number of photos kept aside to be place in frame from Total number of photos

framing in equation form we get;

number of photos to be place in album = 1000 - 10 = 990 photos

Now we will find number of pages needed to place the photos in the album.

number of pages needed to place the photos in the album can be calculated by dividing number of photos to be place in album with number of photos in per page of album.

framing in equation form we get;

number of pages needed to place the photos in the album = $\frac{990}{3}= 330\ pages.$

Hence Sally needed 330 pages of album to place her photos in it.

6 0

2 years ago

Determine the area of the figure shown. Note that each square unit is one unite in length

liq [111]

Answer:

74 units squared

Step-by-step explanation:

we know that the area of a square or rectangle is A = L × w

so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.

so I'll start with the middle square its length is 8 and width is 8 too.

A = 8 × 8

A = 64

now we'll move on to the other small ones to the side.

the one on the right side it's length is 2 and width is 2.

A = 2 × 2

A = 4

and then the last one on the left, Length is 3, width is 2.

A = 2 × 3

A = 6

now we'll add up all of the areas to get the total area.

Total = 64 + 4 + 6

Total = 74 units squared

6 0

3 years ago

(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte

Hunter-Best [27]

(a) If

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then from the given conditions we get the system of equations,

f (-1) = a₀ - a₁ + a₂ - a₃ = -1

f (1) = a₀ + a₁ + a₂ + a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 8a₃ = 1

f (3) = a₀ + 3a₁ + 9a₂ + 27x ³ = 5

(b) Similarly, if

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then

f'(x) = a₁ + 2a₂ x + 3a₃ x ²

so that the given conditions yield the system,

f (1) = a₀ + a₁ + a₂ + a₃ = 0

f' (1) = a₁ + 2a₂ + 3a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 27a₃ = 3

f' (2) = a₁ + 4a₂ + 12a₃ = -1

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2 years ago

Kevin says that “a line segment is the part of a line containing two endpoints.” What additional information is needed to make t

kakasveta [241]

The statement "That does not extend in both directions." will make the definition, precise.

Kevin's line segment definition is correct.

However, the end points in a line segment implies that the line segment does not extend past its two end points.

So, to make it precise;

Kevin needs to include that the line segment does not extend in both directions, in the definition.

Hence, option (c) is correct.