Let x be the number of pens in a box.
Jill : three full boxes of pen and 2 loose pens. 3x + 2
Ben: two full boxes of pen and 14 loose pens. 2x + 14
Jill and Ben have the same pens.
Jill = Ben
3x+2 = 2x + 14
3x - 2x = 14 - 2
1x = 12
x = 12
To check:
Jill = Ben
3x + 2 = 2(x) + 14
3(12) + 2 = 2(12) + 14
36 + 2 = 24 + 14
38 = 38
There are 12 pens or a dozen of pens in a full box.
Answer:
a. x = 5, m∠FGH = 22°
b. m∠HGI = 22°
c. m∠FGI = 44°
Step-by-step explanation:
Since GH bisects FGI this means it divides the angle in two equal parts.
a. solving for x means equating them:
5x-3 = 6x-8 =>
5x - 6x = 3 - 8 =>
x = 5.
Both m∠FGH and m∠HGI are 5*5-3 = 22°
c. Add both angles: m∠FGH + m∠HGI = 44°
(6,2) because X would equals 6 multiplied by 2 equals 12. Now minus 2 and that gives you a equilibrium of 10
(f - 7)/g = h
f - 7 = gh
f = gh + 7
