The length of the leach is 16.05 ft and the area of the mainsail is 64.94 ft²
<h3>What is application of law of sines?</h3>
The law of sines refers to the ratio of side length of triangle to the sine of the opposite angle which is same for all the sides.
SinA / a = SinB/ b = SinC/c
where, the A,B,C are the angles of the triangle and a,b,c are the opposite sides of the angle of triangle.
The mainsail foot is 13 feet long, the luff is 10 feet long has the length of the leach 6.93 ft and the area of the mainsail is 64.85 .
Part A; By using the law of sines;
SinA /10 = SinB / 13
SinA /10 = Sin54 / 13
A = 38.49°
C = 180 - (54 + 38.49)
C = 87.51°
So, Sin38.49 / a = Sin54/ b = Sin87.51/c
Sin38.49 / 10 = Sin54/ 13 = Sin87.51/c
c = Sin87.51 × 13 ÷ Sin54
c = 16.05 ft
Part B; Area of the mainsail = 1/2 × ab SinC
Area = 1/2 × 10 × 13 × Sin87.51
Area = 64.94 ft
Therefore, the length of the leach is 16.05 ft and the area of the mainsail is 64.94 ft²
Read more about the law of sines at; brainly.com/question/17289163
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Answer:
you divide the number by 60 and get 1.83333333 then you have 1 (whole number with 83333333/100000000
Step-by-step explanation:
Answer:
20 square units
Step-by-step explanation:
Area of a parallelogram is calculated with the following formula:
b*h (b: base, h: height)
5*4 = 20 square units
Hello:<span>
the equation is : y = ax+b
the slope is a : a×(-3/2) = -1......(
perpendicular to a line with a slope of -3/2)
a = 2/3 y=(2/3)x+b
the line that passes through (-2, -2) :- 2 =
(2/3)(-2)+b
b = -2/3
<span> the equation is : y = (2/3)x-2/3</span></span>
<span><span>y =(2/3)(x-1)</span></span>
To solve this we are going to use the unitary circle and the fact that
From our circle we can infer that
and
.
Since
,
We can conclude that .
