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yuradex [85]
3 years ago
12

Find the slope of the line passing through the points (-5,6) and (-5,-5)

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0

Hi there! :) :D

Step-by-step explanation:

SLOPE=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}

\frac{(-5)-6}{(-5)-(-5)}=\frac{-11}{0}

<u><em>Undefined.</em></u>

<u><em>Therefore, the slope is -11/0</em></u>

<u><em>Final answer is -11/0</em></u>

Hope this helps!

Thanks!

Have a nice day! :)

:D

-Charlie

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Write equation of the line containing (4,2) and (3,5)<br> in slope-intercept form.
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Answer:

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Step-by-step explanation:

Given the points

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  • (3, 5)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(4,\:2\right),\:\left(x_2,\:y_2\right)=\left(3,\:5\right)

m=\frac{5-2}{3-4}

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We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept

substituting m=-3 and the point (4, 2) to get the y-intercept i.e. b

y=mx+b

2=(-3)4 + b

2 = -12 + b

b = 2+12

b = 14

Now, substituting b=14 and m=-3 in the slope-intercept form to determine the equation of a line in the slope-intercept.

y=mx+b

y=(-3)x+(14)

y=-3x+14

Thus, the equation of the line containing (4,2) and (3,5)  in the slope-intercept form will be:

  • y=-3x+14

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