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Ronch [10]
4 years ago
12

Jacob rolls a number cube numbered 1 to 6. What is the likelihood Jacob rolls a number less than 7?

Mathematics
2 answers:
hichkok12 [17]4 years ago
6 0
0%, the number seven does not fit into the numbers 1-6

Therefore youre likely to roll a number 7 on a dice (1-6) ZERO AMOUNT OF TIMES
Sergio039 [100]4 years ago
3 0
100% because they’re all under 7
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A key code must contain 6 numerals. There are 10 numerals available. Using these numerals, how many different key codes may be c
sattari [20]
Imagine tha the each numeral of the code is written over each line:

__  __  __  __  __  __
1      2    3    4    5   6

Every position may have any of the 10 different numerals.

So over the first line you can put 10 different numerals and the same is true for each of the six positions.

So you can create 10x10x10x10x10x10 = 1,000,000 different codes.
4 0
4 years ago
Identify the initial amount and the growth rate of the following:<br> Y = 9.8 (1.35)^t
stiv31 [10]
Assuming t is a time unit.
The initial amount is when t = 0, so it is 9.8 * 1 = 9.8. The growth rate is how much the amount goes up by for every increase of 1 in t. This is 1.35 because that is the part being affected by t. we plug in 0 for t to get 9.8 as the initial amount. The growth rate is just 135% factor, or 35% more each time, because 1.35 is the base of the exponent.
4 0
3 years ago
Melanie uses 8.1 pints of blue paint and white paint to paint her bedroom walls. 2/5 of this amount is blue paint, and the rest
attashe74 [19]

Answer:

4.86

Step-by-step explanation:

Melanie uses 8.1 pints of blue paint and white paint for her bedroom

2/5 of this amount is blue paint

Therefore the amount of white paint can be calculated as follows

= 2/5

= 0.4×100

= 40%

60/100 × 8.1

= 0.6 × 8.1

= 4.86

Hence 4.86 pints of white paint will be used to paint the bedroom

4 0
3 years ago
A model for tumor growth is given by the Gompertz equation dV dt = a (In b-, In V) V where a &gt;0 and b &gt;0 are constants and
Xelga [282]

Answer:

V(t) = b^{(1-e^{-at})}

Step-by-step explanation:

We are given the following information in the question:

\displaystyle\frac{dV}{dt} = a (In b - In V) V

where a > 0 and b > 0.

\displaystyle\frac{dV}{dt} = a (In b-In V) V\\\\\displaystyle\frac{dV}{dt} = -aV(ln\frac{V}{b})\\\\\frac{dV}{V(ln\frac{V}{b})} = (-a)dt\\\\\text{Put } ln\frac{V}{b} = z\\\\\text{Integrating both sides}\\\\\int \frac{dV}{V(ln\frac{V}{b})} = \int (-a)dt\\\\\text{We get}\\\\\int \frac{dz}{z} = \int (-a)dt\\\\\\\text{where C is the constant of integration}

V(0) = 1~ mm^3\\V(t) = b.e^{e^{-at+C}}\\\text{Putting t =0, V(0) = 1}\\\\V(0) = 1 = b.e^{e^{C}}\\\\V(t) = b^{(1-e^{-at})}

where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.

5 0
3 years ago
Problem 1: Write each expression in the form a^b, without using any radicals.
VARVARA [1.3K]

By radical do you mean the square root symbol?

7 0
3 years ago
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