the real solutions for the equation 
are -
Step-by-step explanation:
= 
= 0
We can write 64 as 
+ = 0
using the identity ( 
)
we get,
= 
= 
....................(1)
solving the quadratic equation ,
=0
solutions of this quadratic equation can be obtained by
let use y for factors
<u />
..................(2)
from the equation 1 we have,
which gives solution 
and from equation 2 we got
so the real solutions for the equation are -
Answer:
10
Step-by-step explanation:
2x3=6
16/4=4
4x3-(6-4)
6-4=2
4x3-(2)
4x3=12
12-(2)
12-2=10
Given that the volume of water remaining in the tank after t minutes is given by the function
where V is in gallons, 0 ≤ t ≤ 20 is in minutes, and t = 0 represents the instant the tank starts draining.
The rate at which water is draining four and a half minutes after it begins is given by
![\left. \frac{dV}{dt} \right|_{t=4 \frac{1}{2} = \frac{9}{2} }=\left[40,000\left(1- \frac{t}{20} \right)\left(- \frac{1}{20} \right)\right]_{t= \frac{9}{2} } \\ \\ =\left[-2,000\left(1- \frac{t}{20} \right)\right]_{t= \frac{9}{2} }=-2,000\left(1- \frac{4.5}{20} \right) \\ \\ =-2,000(1-0.225)=-2,000(0.775)=-1,550\, gallons\ per\ minute](https://tex.z-dn.net/?f=%5Cleft.%0A%20%5Cfrac%7BdV%7D%7Bdt%7D%20%5Cright%7C_%7Bt%3D4%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B9%7D%7B2%7D%20%0A%7D%3D%5Cleft%5B40%2C000%5Cleft%281-%20%5Cfrac%7Bt%7D%7B20%7D%20%5Cright%29%5Cleft%28-%20%5Cfrac%7B1%7D%7B20%7D%20%0A%5Cright%29%5Cright%5D_%7Bt%3D%20%5Cfrac%7B9%7D%7B2%7D%20%7D%20%5C%5C%20%20%5C%5C%20%3D%5Cleft%5B-2%2C000%5Cleft%281-%20%0A%5Cfrac%7Bt%7D%7B20%7D%20%5Cright%29%5Cright%5D_%7Bt%3D%20%5Cfrac%7B9%7D%7B2%7D%20%7D%3D-2%2C000%5Cleft%281-%20%0A%5Cfrac%7B4.5%7D%7B20%7D%20%5Cright%29%20%5C%5C%20%20%5C%5C%20%3D-2%2C000%281-0.225%29%3D-2%2C000%280.775%29%3D-1%2C550%5C%2C%20%0Agallons%5C%20per%5C%20minute)
Therefore, the water is draining at a rate of 1,550 gallons per minute four ans a half minutes after it begins.
Answer option E is the correct answer.
Answer:
875 ft^3
Step-by-step explanation:
Pick them apart starting at the bottom. The formul used is V=lwh
Starting at the bottom we have we have a sqare of 5 ft = 5ft^3= V = 125 ft^3
Then we have a rectangular prism: 5 x 5 x 20 = V = 500 ft^3
Third we have 5 x 5 x 10 = V = 250 ft3
125+500+250 = 875 ft^3
The value of 3 in 6,300 is 10 times the value of 3 in 530. And your welcome.
