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ivolga24 [154]
3 years ago
15

Please help quickly

Mathematics
2 answers:
Sliva [168]3 years ago
4 0

Answer:

A) IS THE CORRECT ANSWER

Lilit [14]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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1-6 greater, less or equal ASAP
Bogdan [553]

Answer:

1: >

2: >

3: =

4: >

5: -2 3/4, -2.2, 3 1/8, 2.8

6: -.6, 4/5, .65, 2/3

Step-by-step explanation:

5 0
3 years ago
Calculate the number of acres required to produce 1,000 gallons of oil in one year from microalgae and soybeans. Which one (micr
Inessa05 [86]

Answer:

microalgae required less space.

Step-by-step explanation:

Amount of oil to be produced = 1,000 gallons

Now,

We know

10,000 gallons of oil is extracted from the miroalgae per acre per year

and,

From soyabeans the oil extracted = 50 gallons per acre per year

therefore,

To produce 1,000 gallons number of acres required by microalgae

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from microalgae]

= 1,000 ÷ 10,000

= 0.1 acres

similarly

To produce 1,000 gallons number of acres required by soyabeans

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from soyabeans]

= 1,000 ÷ 50

= 20 acres

hence,

microalgae required less space.

7 0
3 years ago
A rocket is launched from a tower what time will the rocket reach its max
Lena [83]

Answer:

Step-by-step explanation:

A science class designed a ball launcher and tested it by shooting a tennis ball up and off the top of a 15-story building. They determined that the motion of the ball could be described by the function: h(t) = -16t2 + 144t + 160, where ‘t’ represents the time the ball is in the air in seconds and h(t) represents the height, in feet, of the ball above the ground at time t.

a) Graph the function h(t) = -16t2 + 144t + 160 (see below)

      b) What is the height of the building?

The height of the building is also the height of the tennis ball before it is launched into the air. This occurs when t=0 so substitute 0 for t and you get:

H(0) = -16(0)2 + 144(0) + 160

The height of the building is 160 feet.

 c) At what time did the ball hit the ground?

The ball hits the ground when the height is 0. Therefore, we are looking for a solution to: -16t2 + 144t + 160 = 0

Use the quadratic formula or put this into a calculator. The solution is t=10 and -1, but only 10 makes sense. Therefore, the ball hits the ground at 10 seconds.

  d) At what time did the ball reach its maximum height?

You can put this into the calculator or you can realize that the maximum height is also

− the vertex. The x-value (‘t’ in this case) is 2

−144

which is (2)(−16) = 4.5.

Therefore, the ball reached its maximum height at 4.5 seconds.

   e) What is the maximum height of the ball?

We calculated the time of the maximum height (4.5 seconds). Therefore, substitute 4.5 into the function to find the maximum height.

-16(4.5)2 + 144(4.5) + 160

The maximum height is 484 feet.

5 0
2 years ago
George is 14 years old. His age is 2 years more than twice his brother, Jhon's age. How old is John?
Luda [366]

Answer:

30

Step-by-step explanation:

14×2=28

28+2=30

i hate riddles

8 0
2 years ago
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
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