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jonny [76]
3 years ago
7

The Community College Survey of Student Engagement reports that 46% of the students surveyed rarely or never use peer or other t

utoring resources. Suppose that in reality 40% of community college students never use tutoring services available at their college. In a simulation, we select random samples from a population in which 40% do not use tutoring. For each sample, we calculate the proportion who do not use tutoring. If we randomly sample 100 students from this population, the standard error is approximately 5%. Would it be unusual to see 46% who do not use tutoring in a random sample of 100 students?a) Yes, this would be unusual because 46% is more than one standard error from the mean. It is very rare for a sample to be more than one standard error from mean. b) Yes, this would be unusual because 46% is 6% higher than 40%. c) No, this would not be unusual because the error is only 6%. d) No, this would not be unusual because 46% is only 1.2 standard errors from 40%.
Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

d) No, this would not be unusual because 46% is only 1.2 standard errors from 40%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If the z-score is higher than 2 or lower than -2, X is unusual.

In this question:

Mean = 40%. So \mu = 0.4

Standard error = 5%. So \sigma = 0.05

Is 46% unusual?

We have to find Z when X = 0.46. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.46 - 0.4}{0.05}

Z = 1.2

1.2 is lower than 2, that is, it is only 1.2 standard deviations from the mean.  So 46% is not unusual.

So the correct answer is:

d) No, this would not be unusual because 46% is only 1.2 standard errors from 40%.

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Alecsey [184]

Answer:

a2+b2= (a+b)2 - 2ab

a2+b2= (5)2 + 2(6)

a2+b2= 25+12.

a2+b2= 37

6 0
2 years ago
One of Shakespeare's sonnets has a verb in 11 of its 18 lines, an adjective in 13 lines, and both in 8 lines. How many lines hav
horrorfan [7]

Answer:

Step-by-step explanation:

The total number of lines, n(U) = 18

Let the number of lins with verb be n(V) = 11

Let the number of lines with adjectives be n(A) = 13

n(V n A) = 8

Find the number of lines that have a verb but no adjective, that is, n(V n A')

Mathematically, according to sets theory,

n(V) = n(V n A) + n(V n A')

So,

n(V n A') = n(V) - n(V n A) = 11 - 8 = 3.

Hence, only 3 lines have a verb but no adjectives.

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3 years ago
Find the length of UW(with a line over it) if W is between U and V, UV = 16.8 centimeters, and VW = 7.9 centimeters.
stealth61 [152]

Answer:

8.9 cm

Step-by-step explanation:


We have
\overline {UV} = 16.8 cm\\\\\overline {WV} = 7.9 cm\\\\ Since all lines are scalars, \overline{WV} = \overline{VW}\\\textrm{We see that \overline{UW} + \overline{WV} = \overline{UV}\\\\\overline {UW} \\ = \overline {UV} - \overline {WV} = 16.9 - 7.9 = 8.9 cm}

7 0
1 year ago
3. Given: Circle Q<br>&lt;A = 35<br>Find: m AB​
Agata [3.3K]

Answer:  110°

<u>Step-by-step explanation:</u>

∠A ≅ ∠B  

since ∠A = 35° (given), then ∠B = 35°

Use the Triangle Sum Theorem to find ∠C:

∠A + ∠B + ∠Q = 180°

35° + 35° + ∠Q = 180°

     70°    + ∠Q = 180°

                 ∠Q = 110°

The central angle (∠AQB) ≅ arc AB

since ∠AQB = 110° (solved above), then arc AB = 110°

5 0
2 years ago
Factorize (X + 2 y)square - (2 x minus y) square​
gulaghasi [49]

Answer:

- (x - 3y)(3x + y)

Step-by-step explanation:

Given

(x + 2y)² - (2x - y)² ← expand both parenthesis using FOIL

= x² + 4xy + 4y² - (4x² - 4xy + y²) ← distribute

= x² + 4xy + 4y² - 4x² + 4xy - y² ← collect like terms

= - 3x² + 8xy + 3y² ← factor out - 1 from each term

= - 1(3x² - 8xy - 3y²) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the coefficient of the y² term which sum to give the coefficient of the xy- term.

product = 3 × - 3 = - 9 and sum = - 8

The factors are - 9 and + 1

Use these factors to split the xy- term

3x² - 9xy + xy - 3y² ( factor the first/second and third/fourth terms )

= 3x(x - 3y) + y(x - 3y) ← factor out (x - 3y) from each term

= (x - 3y)(3x + y)

Thus

(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)

3 0
3 years ago
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