How does 10+5x4 to the second power divided by 2 to the third power equal 20?

Which table shows a function that is decreasing only over the interval (–1, ∞)?

aleksandr82 [10.1K]

The table that shows a function that is decreasing only over the interval (–1, ∞) is:

A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 1, negative 3, negative 5, negative 2, negative 1, 2.

<h3>When a function is decreasing?</h3>

A function is decreasing if when we increase the value of x, we decrease the value of y, and vice versa.

Decreasing on the (–1, ∞) means that as x increases on the interval, i.e. x = -100, then x = -10, then x = -2, the value of y decreases. The function that follows this pattern only on this interval is:

A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 1, negative 3, negative 5, negative 2, negative 1, 2.

More can be learned about decreasing functions at brainly.com/question/2649645

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3 0

2 years ago

Let f ( ) sin(arctan ) x x = . What is the range of f ?

nikklg [1K]

So you have composed two functions,
h(x)=sin(x) and g(x)=arctan(x)
→f=h∘g
meaning
f(x)=h(g(x))
g:R→[−1;1]
h:R→[−π2;π2]
And since
[−1;1]∈R→f is defined ∀x∈R

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]
Meaning
f:R→[arctan(−1);arctan(1)]=[−π4;π4]
so there's your domain

5 0

3 years ago

You invested $23,000 in two accounts paying 6% and 7% annual interest, respectively. If the total interest earned for the year w

Sedbober [7]

Answer:

$ 18,000 was invested at 7%, and $ 5,000 was invested at 6%.

Step-by-step explanation:

Given that I invested $ 23,000 in two accounts paying 6% and 7% annual interest, respectively, and the total interest earned for the year was $ 1,560, to determine how much was invested at each rate, the following calculation must be performed:

23,000 x 0.07 + 0 x 0.06 = 1,610

22,000 x 0.07 x 1,000 x 0.06 = 1,600

21,000 x 0.07 x 2,000 x 0.06 = 1,590

20,000 x 0.07 x 3,000 x 0.06 = 1,580

19,000 x 0.07 x 4,000 x 0.06 = 1,570

18,000 x 0.07 x 5,000 x 0.06 = 1,560

Thus, $ 18,000 was invested at 7%, and $ 5,000 was invested at 6%.

3 0

3 years ago

Integer? Yes No −58.5 −11 −287.29 1910 −273

Yuri [45]

Subtract all of your numbers and see what you get