All categories

2 years ago

The radical form plz someone help

Mathematics

1 answer:

Ksivusya [100]2 years ago

5 0

Answer: 4th root of (1/x)^5

Step-by-step explanation: negative exponent makes the x become 1/x. The 4 goes to the outside of the radical, and the 5 stays as the exponent

You might be interested in

Kendra bought 4 boxes of doughnuts. There were 6 doughnuts in each box. She divided the doughnuts equally among 8 people. How ma

Akimi4 [234]

Each person received 3 doughnuts, do 6 times 4 which is 24 and divide that among 8, its 3

3 0

3 years ago

Read 2 more answers

100 POINTS 10 QUESTIONS PLEASE HELP PICTURES BELOW PLEASE SPECIFY WHICH QUESTION YOU ARE ANSWERING

Semenov [28]

Answer:

The answers are $\frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5},$ and $\frac{10}{1}$ .

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

$\frac{2}{5} = \frac{2}{5}$

$\frac{2}{8} = \frac{1}{4}$

$\frac{2}{20} = \frac{1}{10}$

Then, let's do 5:

$\frac{5}{2} = \frac{5}{2}$

$\frac{5}{8} = \frac{5}{8}$

$\frac{5}{20} = \frac{1}{4}$

Note that we already have $\frac{1}{4}$ , so we do not need to include an additional one.

Now, let us do 8:

$\frac{8}{2} = \frac{4}{1}$

$\frac{8}{5} = \frac{8}{5}$

$\frac{8}{20} = \frac{2}{5}$

See how we already have $\frac{2}{5}$ , so we won't have to include that as well.

Finally, let's do 20:

$\frac{20}{2} = \frac{10}{1}$

$\frac{20}{5} = \frac{4}{1}$

$\frac{20}{8} = \frac{5}{2}$

Now see that we already have both $\frac{4}{1}$ and $\frac{5}{2}$ , so we won't have to include both of them, as they are both extras.

Hence, the answers are $\frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5},$ and $\frac{10}{1}$ .

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

8 0

3 years ago

Read 2 more answers

What percent is 29.5 is 10.03

Slav-nsk [51]

The percentage of 29.5 of 10.03 is 2.95885%

5 0

3 years ago

PLEASE HELP MEEEEEEEE!!!

melamori03 [73]

Answer:

d. 9.95h + 5 < 125

Step-by-step explanation:

i hope this helps :)

3 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 180-mg sample. (a) Find the mass that remains after t years. (b) How

DedPeter [7]

Answer:

a) $Q(t) = 180e^{-0.023t}$

b) 11.4mg of cesium-137 remains after 120 years.

c) 225.8 years.

Step-by-step explanation:

The following equation is used to calculate the amount of cesium-137:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount, and r is the rate at which the amount decreses.

(a) Find the mass that remains after t years.

The half-life of cesium-137 is 30 years.

This means that Q(30) = 0.5Q(0). We apply this information to the equation to find the value of r.

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-30r}$

$e^{-30r} = 0.5$

Applying ln to both sides of the equality.

$\ln{e^{-30r}} = \ln{0.5}$

$-30r = \ln{0.5}$

$r = \frac{\ln{0.5}}{-30}$

$r = 0.023$

$Q(t) = Q(0)e^{-0.023t}$

180-mg sample, so Q(0) = 180

$Q(t) = 180e^{-0.023t}$

(b) How much of the sample remains after 120 years?

This is Q(120).

$Q(t) = 180e^{-0.023t}$

$Q(120) = 180e^{-0.023*120}$

$Q(120) = 11.4$

11.4mg of cesium-137 remains after 120 years.

(c) After how long will only 1 mg remain?

This is t when Q(t) = 1. So

$Q(t) = 180e^{-0.023t}$

$1 = 180e^{-0.023t}$

$e^{-0.023t} = \frac{1}{180}$

$e^{-0.023t} = 0.00556$

Applying ln to both sides

$\ln{e^{-0.023t}} = \ln{0.00556}$

$-0.023t = \ln{0.00556}$

$t = \frac{\ln{0.00556}}{-0.023}$

$t = 225.8$

225.8 years.

8 0

3 years ago

Read 2 more answers