<span>2 ^1/2
8 ^1/3 = (2³)^1/3 = 2
12 ^1/4
15 ^1/5
</span>
Step-by-step explanation:
denominators showing all working <3
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
18 pages per hour.
If you do 36 (the pages/amount) divided by 2 (The time), you get 18.
To double check, when you do 90 (The pages/amount) divided by 5 ( The time), then you get 18 again.
Therefore the answer is 18 pages per hour.
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- •Trix•
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Answer:
<h3>D. 12</h3>
Step-by-step explanation:
Which number could be the missing number?
Given the inequality expression, 1/10 > 1/ ?
We are to fine the missing number that will make the inequality true;
Cross multiply:
1 * x > 1*10
x > 10
Hence the value of x greater than 10 is the answer. From the options, the only value greater than 10 is 12. Hence 12 is the correct answer.