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masha68 [24]
3 years ago
13

A large aquarium should contain 10,000 liters of water when it is filled correctly. It will overflow if it gets up to 12,000 lit

ers. The fish will get sick if it gets down to 4,000 liters. The aquarium has an automatic system to help keep the correct water level. If the water level is too low, a faucet fills it. If the water level is too high, a drain opens. One day, the system stops working correctly. The faucet starts to fill the aquarium at a rate of 30 liters per minute, and the drain opens at the same time, draining the water at a rate of 20 liters per minute. How long will it take until the tank starts overflowing or the fish get sick (if it started with 10,000 liters of water)?
Mathematics
1 answer:
never [62]3 years ago
4 0

Answer:

The water level is rising because it is filling 10 more liters than it is draining

16.7 hours

Step-by-step explanation:

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Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

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3 years ago
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Answer:

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Can someone please help me
azamat

Given:

angle ECB=51 degrees

=>

angle EOB = 2*angle ECB = 2*51 = 102 degrees = arc EAB


Also given minor arc AB = 72 degrees

therefore

minor arc EA = 102-72=30 degrees

5 0
3 years ago
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