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lozanna [386]
3 years ago
12

If 45 cookies serve 15 students how many cookies will serve 30 students

Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0

Answer:

45:15  45 cookies for every 15 students

90:30  90 cookies for every 30 students


Mamont248 [21]3 years ago
5 0

Answer:

90 cookies would be served to 30 students.

Step-by-step explanation:

First, simplify the first ratio given to us.

45/15 = 3/1

Every student is given 3 cookies. You are now serving 30 students. To solve, multiply 3 with 30.

3 x 30 = 90

90 cookies would be served to 30 students.

~

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HELP! 8TH GRADE MATH PLS LOL
LekaFEV [45]
<h2><u>Given</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{x =  - 8}}}

<h2><u>Solution</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  = 3 \times  - 8 + 34}}}

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  =  - 24 + 34}}}

{ \large{ \bf{ ➢ \:  \: \cancel{2}y = 3 \times { \cancel{(10)} {} \:  \:  ^{5} }}}}

{ \large{ \therefore{  \bf{y = 15 \:  \: Ans.}}}}

3 0
3 years ago
What is the common difference, d, in the arithmetic sequence defined by the formula below? an=2n+1
marishachu [46]
<h3><u>Answer:</u></h3>

  • d = 2

<h3><u>Solution:</u></h3>

We are given that the arithmetic progression is defined by :

➝ 2n + 1

<em>Therefore, </em>

  • <u>For </u><u>first </u><u>term</u>

➙ n = 1

➝ 2 × 1 + 1

➝ 2 + 1

➝ 3

  • <u>For </u><u>second </u><u>term</u>

➙ n = 2

➝ 2 × 2 + 1

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➙ 2nd term - 1st term

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➝ 2

<h3><u>More </u><u>information</u><u>:</u></h3>

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2 years ago
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Answer:

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Step-by-step explanation:

7/8, with the given denominator 40

So how do we get 8, to turn into 40?

Simple multiplication.

8x5 = 40, and whatever we multiply times the denominator, we multiply for the numerator.

So

7x5 = 35

The answer should be 35/40

8 0
3 years ago
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tankabanditka [31]
7.C I think is the answer
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