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user100 [1]
2 years ago
14

Jamal is running 42 kilometers. The amount of time t it takes Jamal to run varies inversely with the rate, r, at which he runs,

write the inverse variation equation that represents this situation
Mathematics
1 answer:
leva [86]2 years ago
6 0

Answer:

t α 1 /r ; t = k/r

Step-by-step explanation:

Given that :

Time taken, t varies inverse as rate, r

MATHEMATICALLY,

t α 1 /r

Hence,

t = k/r ;

Where, k is the proportionality constant

Hence, the situation could be expressed as :

t = k/r OR

t α 1 /r

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Jackie is selling smoothies at a school fair. She starts the day with $15 in her cash box to provide change to her customers. If
Liula [17]

Answer:

ىر سيىخرسىي ىتسيرىتسهارسيخهكتر يسرلاتزسنيى يتريزىيسئرتسئرة سينرةظسئر سظرى ئمرىسنرمسيىمر سئرىسئنرتىئسر ؟

8 0
3 years ago
As a salesperson for an electronic parts distributor, you are given two options for your salary structure. The first option has
kumpel [21]

Answer:

The amount of sale is approximately 5714.

Step-by-step explanation:

Let x be the sales made that will result to the same salary and let y be the same weekly salary.

We can represent both salaries as follows:

300 + 0.04x = y

100 + 0.075x = y

Subtracting the second equation from the first, we have:

200 – 0.035x = 0

0.035x= 200

x = 200/0.035

x ≈ 5714.

Therefore, the amount of sale is approximately 5714.

3 0
3 years ago
Under his cell phone plan Jason pays a flat cost of $60.50 per month and four dollars per gigabyte he wants to keep his bill at
Over [174]

Answer:

2 gigabytes of data

Step-by-step explanation:

Given

Amount Jason keeps per month = $68.90

Cost of flat per month = $60.50

Balance for data = 68.90-60.50

Balance for data = $8.40

If 1Gigabyte = $4

x = $8.40

Cross multiply

4x = 8.40

x = 8.40/2

x = 2.20

Hence Jason can only use 2 gigabytes of data while staying within his budget

7 0
2 years ago
Read 2 more answers
The sum of 14 and 3<br> divided by r
labwork [276]

Answer:

?

Step-by-step explanation:

7 0
3 years ago
Suppose a certain home improvement outlet knows that the monthly demand for framing studs is 2,300 when the price is $4.77 each
pogonyaev

Answer:

p + 0.0001q = 5

Step-by-step explanation:

Data provided in the question:

When Price, p₁ = $4.77 ; Demand, q₁ = 2,300

and,

When Price, p₂ = 3,300 ; Demand, q₂ = 3,300

considering the above as the points on the line,

now, the general equation for a line is given as:

\frac{q_1-q}{p_1-p}=\frac{q_2-q_1}{p_2-p_1}

on substituting the respective values, we get

\frac{2,300-q}{4.77-p}=\frac{3,300-2,300}{4.67-4.77}

or

\frac{2,300-q}{4.77-p}=\frac{1000}{-0.1}

or

2,300 - q = -10,000(4.77 - p)

or

⇒ 2,300 - q = -47700 + 10,000p

or

⇒ 10,000p + q = 2300 + 47700

or

⇒ 10,000p + q = 50000

or

⇒ p + 0.0001q = 5

8 0
3 years ago
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