A tank, shaped like a cone has height 11 meter and base radius 4 meter. It is placed so that the circular part is upward. It is

Question

3 years ago

11

A tank, shaped like a cone has height 11 meter and base radius 4 meter. It is placed so that the circular part is upward. It is

full of water, and we have to pump it all out by a pipe that is always leveled at the surface of the water. Assume that a cubic meter of water weighs 10 000 N

Mathematics

1 answer:

aksik [14] · Answer 1 · 2021-12-18T19:07:09+03:00

aksik [14]3 years ago

3 0

Answer:

The tank is a cone, so the radius of the cross section increases linearly with h

At y=0, r=4 and at y=11, r=0

So

r(y)=4/11 (11−y)

A(y)=π[4(11−y)11]^2

Integral will be:

11∫0 (1000)(9.8)(4πy^2)(25)(11−y)dy

Step-by-step explanation: