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aliya0001 [1]
3 years ago
13

Take a look at the statement below: Fish meal is better than artificial fertilizers. How could this statement be revised to make

it a hypothesis? Fish meal is safer than artificial fertilizers, but it does not make plants grow. Fish meal is a better fertilizer than artificial fertilizer because fish meal is natural. Plants that are fertilized with fish meal will grow taller than plants that receive artificial fertilizer. Plants that receive artificial fertilizer will be better than plants that receive fish meal.
Biology
2 answers:
Naily [24]3 years ago
9 0

The correct answer is that Plants that are fertilized with fish meal will grow taller than plants that receive artificial fertilizer.

The hypothesis that Fish meal is better than artificial fertilizer. The revised statement to this hypothesis could explain the effect of fish meal which affects the plant in a better way when compared to artificial fertilizers. The plants fed with fish meal will grow taller than plants that are fed with artificial fertilizer.

V125BC [204]3 years ago
4 0
The question is asking to state which of the following is the revised statement that would make the sentence as a hypothesis, base on my research and analysis, I would say that the answer would be "<span>Plants that are fertilized with fish meal will grow taller than plants that receive artificial fertilizer</span>" 
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Iron-55 has a half-life of 3 years. How much of a 40 gram sample will remain after 12 years? A. 0 grams B. 4 grams C. 2.5 grams
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Answer:

\boxed {\boxed {\sf C. \ 2.5 \ grams }}

Explanation:

We are asked to find how much of a 40 gram sample remains after 12 years.

Iron-55 has a half-life of 3 years. Therefore, after 12 years, 4 half-lives have been completed.

  • 12 years/3 years = 4 half-lives

Every time a half-life is completed, half of the sample's mass decays. Remember we start with a 40 gram sample.

  • 1 half- life: 40 g / 2 = 20 g
  • 2 half-lives: 20 g / 2= 10 g
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There is also a formula that can be used to solve this problem.

A= A_o(\frac {1}{2})^{\frac{t}{hl}

Where A₀ is the initial amount, t is the time, and hl is the half-life.

We know 40 grams is the inital amount, 12 years is the time, and 3 years is the halflife.

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A= 40 \ g (\frac{1}{2})^\frac{12}{3}

A= 40 \ g (\frac{1}{2})^4

A= 40 \ g * 0.0625

\bold {A= 2.5 \ g}

After 12 years, <u>2.5 grams </u> of Iron-55 will remain.

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