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scoundrel [369]
3 years ago
7

Factor 36x^2 + 11x-12 please hurry​

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
5 0

Answer:

The answer is

<h2>(9x - 4)(4x + 3)</h2>

Step-by-step explanation:

36x² + 11x - 12

To factor the expression rewrite 11x as a difference

That's

36x² + 27x - 16x - 12

<u>Factor out 9x from the expression</u>

9x( 4x + 3) - 16x - 12

<u>Factor out - 4 from the expression</u>

9x( 4x + 3) - 4( 4x + 3)

Factor out 4x + 3 from the expression

We have the final answer as

<h3>(9x - 4)(4x + 3)</h3>

Hope this helps you

KATRIN_1 [288]3 years ago
4 0

Answer:

(9x - 4)(4x + 3)

Step-by-step explanation:

36x² + 11x - 12

(9x - 4)(4x + 3)

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A right cylinder has a radius of 3 and a height of 12. What is its surface area?
shepuryov [24]

Answer:

Surface Area = 283

Step-by-step explanation:

Radius = 3

Height = 12

Formula for suface area is SA= 2πrh+2πr^2

let "r" be for radius

let "h" be for height

SA=2*π*3*12+2*π*3^2

SA=282.74

round to the nearest ones spot and that will make the surface area = 283

8 0
3 years ago
Please Help me answer all 4 questions with a full explanation so I can solve the rest on my own.
Nata [24]

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\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}

\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}

\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6

6 0
2 years ago
HELP PLEASEEE!!!! I START SCHOOL TOMORROW
ohaa [14]

Answer:

4. The range is -2 ≤ y ≤ 4

5. The domain is {-2 , -1 , 0 , 3.5 , 4.2}

6. The relation is not a function

Step-by-step explanation:

* Lets explain how to solve the problem

# Question 4:

- The range of the function is the values of all y (output) which is

 corresponding to the values of all x (input)

- The figure is a stare, the values of x is from -4 to 4

∴ The domain is -4 ≤ x ≤ 4

- The corresponding values of y are from -2 to 4

∴The range is -2 ≤ y ≤ 4

# Question 5:

- The table represent a relation between x and y

- x is the input of the relation

- y is the output of the relation

∵ The input of the relation is called the domain of it

∴ The domain of the relation is all values of x in the table

- the values of x are -2 , -1 , 0 , 3.5 , 4.2

∴ The domain is {-2 , -1 , 0 , 3.5 , 4.2}

# Question 6:

- The relation can be a function if each ordered pair has a

  unique value of x (input)

- That means every x (input) has only one y (output)

- Ex : The relation {(a , b) , (c , d) , (a , f)} is not a function because

 the input a has two output b and f

∵ The relation is {(-4 , 0) , (-3 , 0) , (-2 , 1) , (1 , -2) , (-3 , 4)}

∵ The x = -3 has two values of y 0 and 4

∴ The relation is not a function

7 0
3 years ago
After a reflection, can A=A'?
motikmotik
NO It can not!

Reason: the reason is because since both are the same , it will equal the mostly 0! So it wouldn’t make sense. So no!

Hoped I help mark brainly it would help me a lot!
4 0
3 years ago
WILL MARK AS BRAINLIEST FOR THESE QUESTIONS.
laiz [17]

1.

Let the sandwich be represented by = x

Let the drink be represented by = y

As given, Joe charges $10.00 for two sandwiches and one drink, so equation becomes 2x+y=10    ....(i)

He charges $6.50 for one sandwich and one drink, so equation becomes x+y=6.50  ....(ii)

Subtracting (ii) from (i) we get

x=3.50

And as x+y=6.50

y=6.50-3.50=3.00

Hence, cost of a sandwich is $3.50 and a drink is $3.00

2.

the question is incomplete. coordinates are missing

3.

Let x represent the number of performances

cost = 8000+300x

revenue = 700x

To break even, the cost must be equal to the revenue.

8000+300x=700x

400x=8000

so x=20

Hence, 20 performances are needed to break even.

4.

Let us take x for 20% material, y for 50% material

\frac{20x+50y}{200}=30

20x+50y=6000    ......... (1)

Accounting for volumes to use, x+y=200 or x=200-y ................ (2)

Putting the value of x in (1)

20(200-y)+50y=6000

4000-20y+50y=6000

4000+30y=6000

30y=2000

y=66.67

x=200-y = 200-66.67 =133.33

Hence, 133.33 ml of 20% acetic acid and 66.67% of 50% acetic acid is needed.





3 0
3 years ago
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