A small business owner made $30,000 the first year he owned his store and made an additional 2 over the previous year in each su
1 answer:
You might be interested in
Part A.
1) Function given:
2) Interpretation:
initial value: => x = 0 => f(x) = 0.69
table:
x f(x)
year price
0 0.69
1 0.69 * 1.03 = 0.7107 => increase = 3%
2 0.69 * (1.03)^2 = 0.732021 => increase = 3%
So, the answer is that the function is increasing at 3% per year.
Part B.
3) table
<span> t (number of years) 1 2 3 4
f(t) (price in dollars) 10,100 10,201 10,303.01 10,406.04
Percent change:
Year 2: 10,201 / 10,100 = 1.01 => 1% increase
Year 3: 10,303.01 / 10,201 = 1.01 => 1% increase
Year 4: 10,406.04 / 10,303.01 = 1.01 => 1% increase.
Answer: the </span><span>product of the part A recorded a greater percentage change in price over the previous year (3% vs 1%).</span>
1) Function given:
2) Interpretation:
initial value: => x = 0 => f(x) = 0.69
table:
x f(x)
year price
0 0.69
1 0.69 * 1.03 = 0.7107 => increase = 3%
2 0.69 * (1.03)^2 = 0.732021 => increase = 3%
So, the answer is that the function is increasing at 3% per year.
Part B.
3) table
<span> t (number of years) 1 2 3 4
f(t) (price in dollars) 10,100 10,201 10,303.01 10,406.04
Percent change:
Year 2: 10,201 / 10,100 = 1.01 => 1% increase
Year 3: 10,303.01 / 10,201 = 1.01 => 1% increase
Year 4: 10,406.04 / 10,303.01 = 1.01 => 1% increase.
Answer: the </span><span>product of the part A recorded a greater percentage change in price over the previous year (3% vs 1%).</span>
The answer to this problem is all real numbers except for 4. When looking at this function, one can see that most numbers are possible. But, the only number that won't be possible is four. That's because the fraction 
will always equal something greater than or less than zero. Since it's never going to equal zero, and since there is already a 4, that means that the range of this function is all real numbers except for 4.