Answer:
900
Step-by-step explanation:
natural numbers are all positive numbers that dont include 0
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
477.47 revolutions
Step-by-step explanation:
From the information given:
The formula for calculating the circumference = 2π r
Given that the radius of each wheel = 25 centimeter
Then, the circumference = 2 π (25)
= 50π cm
The distance traveled in 5 minutes is as follows:
Given that:
The speed = 45 km/ hour
i.e.
1 hour = 45 km
In an hour, we have 60 minutes
So, 60 minutes = 45 km
1 minute = 45/60 = 0.75 km
To cm;
0.75 km = (0.75 × 1000) m = 750 m
750 m = 750 × 100 = 75,000 cm
∴
The number of revolution in 5 minutes sInce 1 revolution = 50π cm is:
= 75,000 cm/ 50π cm
= 477.47 revolutions in 5 minutes
Answer:
Function: absolute value function
Transformations: Vertical stretch by a factor of 2, horizontal shift three units to the left, and vertical shift five units down.
Let me know if this helps!
