if angle m=(25x+1)degrees, angle c=(25x-2)degrees, angle d=(20x-1)degrees, and angle b=82 degrees what is angle a

Variance is: Multiple Choice the average squared deviations about the mean of a distribution of values. an empirically testable

DENIUS [597]

Multiple choice answers are clearly defined as below for clarity:

A. the average squared deviations about the mean of a distribution of values.

B. an empirically testable statement that is an unproven supposition developed in order to explain certain phenomena.

C. the error made by rejecting the null hypothesis when it is true.

D. a statement that asserts the status quo; that is, any change from what has been thought to be true is due to random sampling order.

E. a statement that is the opposite of the null hypothesis

Answer:

A. The average squared deviations about the mean of a distribution of values.

Explanation:

A. the average squared deviations about the mean of a distribution of values. Correct

Standard deviation is how data is distributed around the mean. It is also the square root of the Variance. Therefore, the variance is the square of the standard deviation which is distributed around the mean.

B. an empirically testable statement that is an unproven supposition developed in order to explain certain phenomena. Incorrect

This is false as this is rather the definition for hypothesis.

C. the error made by rejecting the null hypothesis when it is true. Incorrect

This is false as this is the definition for the probability of committing a type I error

D. a statement that asserts the status quo; that is, any change from what has been thought to be true is due to random sampling order. Incorrect

This is false as this defines what a null hypothesis is.

E. a statement that is the opposite of the null hypothesis. Incorrect

The opposite of the null hypothesis is alternative hypothesis.

6 0

3 years ago

Simplify (2x-2)/(x-1). Show work.

kozerog [31]

Answer:

$\frac{(2x - 2)}{(x - 1)}$

$= \frac{2(x - 1)}{x - 1}$

$= 2$

3 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

Which of the binomials below is a factor of this trinomial?

Degger [83]

The factor is (x+6)(x+6)
So, D. x+6 is the correct answer :)

5 0

3 years ago

I really dont get it what does it mean

svetoff [14.1K]

So basically what this is trying to tell you is are they mutiples / equal to each other, also a rule. Its A. because 25 x 2 = 50, then 50 x 2 = 100 and so on.

So the answer is A

Hope it helps! :D

4 0

3 years ago

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