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3 years ago

Which of the following terms is defined as "a point that divides a segment into two congruent segments"?

Mathematics

2 answers:

Bond [772]3 years ago

3 0

I would say D midpoint! Hope this helps :)

earnstyle [38]3 years ago

3 0

Bisector of a segment – line, ray segment, or plane that divides a segment into two congruent segments. Midpoint of a segment – a point that divides thesegment into two congruent segments. Acute angle – angle whose measure is between 0 degrees and 90 degrees. Right angle – angle whose measure is 90 degrees.

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15 x sin(30)=?/15 x 15

Delicious77 [7]

Answer:

The exact value of

sin

(

)

sin(30) is

12.

⋅

15⋅12

Combine

15 and

12.

152

The result can be shown in multiple forms.

Exact Form:

152

Decimal Form:

7.5

Mixed Number Form:

712

Step-by-step explanation:

8 0

2 years ago

What is the equivalent fraction of 2/6

Leto [7]

1/3 because 2/6 divided 2/2 equals 1/3

6 0

3 years ago

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Please help asap!! I will mark you as brainliest. :)

Ratling [72]

The measure of the angle 5 is hekdbssj and the rleation

5 0

3 years ago

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What is the mean of the following set of numbers rounded to the nearest whole number?

timama [110]

The mean is when you add up all the numbers and divide by the amount of numbers there are.
143+312+41+28+308+619+321+352+465=2589
2589/9=287.666666667
round to the whole number you get
288

4 0

3 years ago

[SCREENSHOT INCLUDED] If f(x) = sqrt(2x+1) then f '(4) =

Sphinxa [80]

Using the definition,

$f'(4) = \displaystyle \lim_{x\to4} \frac{f(x)-f(4)}{x-4}$

The numerator in the difference quotient is

$f(x) - f(4) = \sqrt{2x+1} - \sqrt{2\cdot4+1} = \sqrt{2x+1}-3$

Multiply the numerator and denominator by the conjugate of this expression,

$\displaystyle \frac{\sqrt{2x+1}-3}{x-4} \cdot \dfrac{\sqrt{2x+1}+3}{\sqrt{2x+1}+3}$

The modified numerator reduces to a difference of squares,

$\displaystyle \frac{\left(\sqrt{2x+1}\right)^2-3^2}{(x-4)\left(\sqrt{2x+1}+3\right)}$

Simplify this to get

$\displaystyle \frac{2x+1-9}{(x-4)\left(\sqrt{2x+1}+3\right)} = \frac{2(x-4)}{(x-4)\left(\sqrt{2x+1}+3\right)}$

Since x is approaching 4, it never actually takes on the value of 4, so (x - 4)/(x - 4) reduces to 1. Then the limit is equivalent to

$f'(4) = \displaystyle \lim_{x\to4} \frac{f(x)-f(4)}{x-4} = \lim_{x\to4}\frac2{\sqrt{2x+1}+3}$

and the remaining limand is continuous at x = 4, so that

$f'(4) = \dfrac2{\sqrt{2\cdot4+1}+3} = \dfrac26 = \boxed{\dfrac13}$

6 0

2 years ago