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joja [24]
4 years ago
12

Rearrange the equation below to solve for y. 4y - 3a = 13a

Mathematics
2 answers:
Readme [11.4K]4 years ago
6 0

Answer:

\boxed{\huge {\sf y = 4a}}

Step-by-step explanation:

\sf Solve  \: for \:  y: \\  \sf \implies 4y - 3a = 13a \\  \\  \sf Add  \: 3a  \: to  \: both \:  sides: \\  \sf \implies 4y + ( \boxed{ \sf 3a} - 3a) = \boxed{ \sf 3a} + 13a \\  \\  \sf 3a - 3a = 0 :  \\  \sf \implies 4y = 3a + 13a \\  \\  \sf 3a + 13a = 16a :  \\  \sf \implies 4y = 16a \\  \\  \sf Divide \:  both  \: sides  \: by  \: 4: \\  \sf \implies \frac{4y}{ \boxed{ \sf 4}}  =  \frac{16a}{ \boxed{ \sf 4}}  \\  \\  \sf \frac{4y}{4}  =  \frac{ \cancel{ \sf 4}}{\cancel{ \sf 4}}   \times y = y :  \\  \sf \implies y =  \frac{16a}{4}  \\  \\  \sf  \frac{16a}{4} =  \frac{\cancel{ \sf 4} \times 4a}{\cancel{ \sf 4}}   = 4a :  \\  \sf \implies y = 4a

Vilka [71]4 years ago
3 0
Hi there!

The rearranged equation solving for y is “y = 4a”

Move all the terms not containing the y to the right side of the equation.

4y = 16a

Then divide both sides by 4!

Hope this helps!
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