Es x2 o 2x ? Porque con x2 no se podrá resolver, tendría que ser 2x
Answer:
The way I was taught to do it is to change value into a total fraction, then multiple the numerators together, multiply the denominators together, and finally reduce as far as possible.
7/9 x 5 2/5 = 7/9 x 27/5 = 189/45 = 4 9/45 = 4 1/5
1 3/4 x 4 1/6 = 7/4 x 25/6 = 175/24 = 7 7/24
Remember
(x^m)(x^n)=x^(m+n)
and
if a^m=a^n, where a=a then n=m
(x^4)(x^n)=x^5
(x^4)(x^n)=x^(4+n)
x^(4+n)=x^5
therefor
4+n=5
minus 4
n=1
