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2 years ago

Name a point that is the square root of 2 away from(-1,5)

Mathematics

1 answer:

DerKrebs [107]2 years ago

3 0

Answer:

Any point on the circle (x + 1)² + (y - 5)² = 2 with center (-1 , 5) and radius √2

Step-by-step explanation:

circle: (x + 1)² + (y - 5)² = 2

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Any help would be appreciated! <br> 7/9+ 8/9 as a mixed number

katovenus [111]

Answer:

15/9 :))

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7 0

2 years ago

Read 2 more answers

Select ALL the correct answers.

stiv31 [10]

Answer:

Statements 3, 4 and 5 are true.

Step-by-step explanation:

x^2 - 8x + 4

Using the quadratic formula:

x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2

= (8 +/- √(64 - 16)) / 2

= 4 +/- √48 / 2

= 4 +/- 4√3/2

= 4 +/- 2√3.

So the third statement is true.

Converting to vertex form:

x^2 - 8x + 4

= (x - 4)^2 - 16 + 4

= (x - 4)^2 -12

So the extreme value is at (4, -12)

So the fourth statement is true.

The coefficient of the term in x^2 is 1 (positive) so the graph has a minimum.

4 0

2 years ago

Gary wants to buy a video game with a price of $48 the game is marked as 50% off and the sales tax in his state is 4.5%

notka56 [123]

48/2=24
24×.045=1.08
24+1.08=$25.08 to purchase the game

3 0

2 years ago

Please help me with the question

Damm [24]

Answer:

The right answer is Option 2:

$y+6 = -\frac{3}{4}(x-2)$

Step-by-step explanation:

Point-slope form of equation of a line is given by:

$y-y_1 = m(x-x_1)$

Here m is slope of the line and (x1,y1) is the point from which the line passes.

Given

Slope = m = -3/4

Point = (x1,y1) = (2,-6)

We simply have to put these value into the general form of equation of line in point-slope form

$y-(-6) = -\frac{3}{4}(x-2)\\y+6 = -\frac{3}{4}(x-2)$

Hence,

The right answer is Option 2:

$y+6 = -\frac{3}{4}(x-2)$

7 0

2 years ago

Please! Solve f(x)-g(x) if f(x)=1/2x^4 - x^2 and g(x)= 3/4x^4 +3x^3 - x^2

igomit [66]

Answer:

$f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}$

Step-by-step explanation:

This is a subtraction between polynomials, since both functions are polynomials, hence, to solve the problem with need to perform the subtraction, by coefficients.

$f(x)= \frac{1}{2}x^{4}+0x^{3}-x^{2}\\\\g(x)=\frac{3}{4}x^{4}+3x^{3}-x^{2}$

By performing the subtraction, we have:

$f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}$

6 0

2 years ago