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3 years ago

6

Choose the correct simplification of f to the 9th power times h to the 23rd power all over f to the 3rd power times h to the 17t

h power

1 answer:

klio [65]3 years ago

7 0

If you subtract 3 from 9 you get 6, so it would be f^6 and if you subtract 17 from 23 you get 6 also, so it would be h^6

f^6h^6, I believe the answer is c.

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Which letter represents the result of subtracting zz from

Helga [31]

Answer:

b hpárrafo sobre mi casa

benglesio no seinew

Step-by-step explanation:

8 0

3 years ago

Assume that the number of watches produced every hour is normally distributed with a mean of 500 and a standard deviation of 100

horsena [70]

To evaluate the <span>probability that in a randomly selected hour the number of watches produced is greater than 500 we proceed as follows:
z=(x-</span>μ<span>)/</span>σ
where:
x=500
μ=500
σ=100
thus
z=(500-500)/200=0

Thus:
P(x>500)=1-P(x<500)=1-P(z<0)=1-0.5=0.5

Answer: 0.5~50%

8 0

3 years ago

Read 2 more answers

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

3 years ago

What is the logarithmic function modeled by the following table? x f(x) 9 2 27 3 81 4

Nataly_w [17]

Answer:

Required logarithmic function is :

$f\left(x\right)=\log_3\left(x\right)$

Step-by-step explanation:

We have been fiven that table for the logarithmic function is:

x f(x)

9 2

27 3

81 4

which can be rewritten as:

x f(x)

3^2 2

3^3 3

3^4 4

Which are basically powers of 3

So we can use logarithmic function as

$\log_3\left(9\right)=\log_3\left(3^2\right)=2\log_3\left(3\right)=2(1)=2$

Hence required logarithmic function is :

$f\left(x\right)=\log_3\left(x\right)$

8 0

3 years ago

X - 5 < - 3 <br> Or<br> X + 8 > 2

Alex Ar [27]

Step-by-step explanation:

x-5 < -3

or, x < -3 +5

or, x < 2

Now,

x +8 >2

or, x >2 - 8

or, x >-6

7 0

2 years ago