$\dfrac{4y+5}{3}=\dfrac{y-8}{2}\qquad\text{multiply both sides by }\ 2\cdot3=6\\\\6\!\!\!\!\diagup^2\cdot\dfrac{4y+5}{\not3_1}=6\!\!\!\!\diagup^3\cdot\dfrac{y-8}{\not2_1}\\\\2(4y+5)=3(y-8)\qquad\text{use distributive property}\\\\(2)(4y)+(2)(5)=(3)(y)+(3)(-8)\\\\8y+10=3y-24\qquad\text{subtract 10 from both sides}\\\\8y=3y-34\qquad\text{subtract 3y from both sides}\\\\5y=-34\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{34}{5}}$

5 0

3 years ago

Given f(x) = 2x^2 -3x and g(x) = x+4

Alenkasestr [34]

Answer:

2x³ + 5x² - 12x

Step-by-step explanation:

The correct answer doesn't seem to be listed...

(fg)(x) = (2x² - 3x)(x + 4)

Which equals...

2x²(x) + 2x²(4) + (-3x)(x) + (-3x)(4)

Which simplifies to...

2x³ + 8x² - 3x² - 12x

2x³ + 5x² - 12x

8 0

3 years ago

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Evaluate StartFraction 3 (6 minus 14) over negative 4 EndFraction.<br> -15<br> -6<br> -1<br> 6

11111nata11111 [884]

Answer:

Step-by-step explanation:

First you would do 6 minus 14 and end up with -8

Then you would do -8 times 3 which equals -24

Lastly you would do -24 divided by -4 and get 6

4 0

3 years ago

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I need this ASAP!!!! PLZ HELP!!! 20 points!!

sergiy2304 [10]

Answer:

Third graph C.

Step-by-step explanation:

3a + 11 > 5

Subtract 11 from both sides

3a > -6

Solve for a

a = -6/3

a > -2

so a would be all numbers greater than -2

7 0

2 years ago

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