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3 years ago

7

Connor have six employees and Bob 41 uniforms for them if you wanted to give them the same number of uniforms so he doesn't have

any extra

2 answers:

bagirrra123 [75]3 years ago

6 0

It will be 6 to each person because 6x6 is 36 if u do 6x7 it will be 42 and it said 41 t-shirts not 42

Nadya [2.5K]3 years ago

5 0

It would be 6 because if you do 6 times 7, it would be 42 and that is higher than 41. 6x6=36.

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2n+(7n+8)= what is the missing coefficient

Taya2010 [7]

Assuming that you were to simplify this, you'd get 2n + 7n + 8 = 9n + 8.

6 0

3 years ago

How do you solve 3+56684

romanna [79]

Just make the problem into a form in which you can solve

56684
+ 3

Add 3
Final Answer: 56687

5 0

3 years ago

Read 2 more answers

An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.

strojnjashka [21]

Answer:

1. The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

2. The point estimate for the true difference between the population means is of -1872.

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of Normal Variables:

When two normal variables are subtracted, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 212 brakes using Compound 1 yields an average brake life of 47,895 miles. The population standard deviation for Compound 1 is 1590 miles.

This means that $\mu_1 = 47895, \sigma_1 = 1590, n = 212, s_1 = \frac{1590}{\sqrt{212}} = 109.2$

A sample of 180 brakes using Compound 2 yields an average brake life of 49,767 miles. The population standard deviation for Compound 2 is 4152 miles.

This means that $\mu_2 = 49767, \sigma_2 = 4152, n = 180, s_2 = \frac{4152}{\sqrt{180}} = 309.47$

True difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2.

This is the distribution 1 - 2. So

$\mu = \mu_1 - \mu_2 = 47895 - 49767 = -1872$

This is also the point estimate for the true difference between the population means, which is question 2.

$s = \sqrt{s_1^2+s_2^2} = \sqrt{109.2^2+309.47^2} = 328.17$

90% confidence interval

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = zs = 1.645*328.17 = 539.84$

The lower end of the interval is the sample mean subtracted by M. So it is -1872 - 539.84 = -2411.84

The upper end of the interval is the sample mean added to M. So it is -1872 + 539.84 = -1332.16.

The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

5 0

3 years ago

The length of a rectangle is 3 times the width. The perimeter is 44 cm. What are the dimensions of the rectangle? Write and solv

ser-zykov [4K]

Here are your equations:
x and 3x
How to set up:
2(x)+ 2(3x) = 44
Simplify:
8x = 44
Divide:
x = 5.5
Plug back in to find values:
Width = 5.5
Length = 16.5

Hope this helps!! :)

5 0

3 years ago

Solve the differential equation dy/dx=2*y/x,x>0 simplify?

Andrew [12]

Separate your variables:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2y}x\implies \dfrac{\mathrm dy}y=2\dfrac{\mathrm dx}x$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dy}y=2\int\frac{\mathrm dx}x\implies \ln|y|=2\ln|x|+C\implies y=e^{2\ln|x|+C}=Cx^2$

4 0

4 years ago