Question

What is the range of y = sin-1x? [–1, 1] [0, π] left-bracket negative startfraction pi over 2 endfraction, startfraction pi over 2 endfraction right-bracket (–[infinity], [infinity])

Answer 1

The range of the provided inverse sine function in terms of x, and y y = sin-1x is [-π/2, π/2].

What is the range of the function?

Range of a function is the set of all the possible output values which are valid for that function.

The trigonometry function given in the problem is,

$y = \sin^{-1}x$

The above function can be written as,

$\sin y = x$

The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.

$-1\leq x\leq1$

This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,

$-\dfrac{\pi}{2}\leq x\leq\dfrac{\pi}{2}$

Thus, the range of the provided inverse sine function in terms of x, and y y = sin-1x is [-π/2, π/2].

Learn more about the range of the function here;

brainly.com/question/2264373