Answer:
10000
Step-by-step explanation:
there is a simple formula to remember.
the sum of n odd number = n^2
so for the sum of 100 positive odd numbers = (100)^2=10000
Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
Answer:
12=12
Step-by-step explanation:
Answer:
3 is the correct answer...
Answer:
I think its the first answer
Step-by-step explanation:
