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3 years ago

10. And 11. Please help right now

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

6 0

10.
There are 100 cm in a meter. So, in order to find out the fraction, you put the number of centimeters over 100.
43/100 meters
In order to find the decimal, you just divide the top by the bottom and you get 0.43 meters

11.
There are 10 decimeter in a meter. So, in order to find out the fraction, you put the number of decimeter over 10.
6/10=3/5 meters
To find the decimal, you divide the top by bottom and you get
0.6 meters.

Hope this helped!

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The answer 4/4 is equal to 1.

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3 years ago

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d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

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3 years ago

Ajar contains 16 beads. 4 beads are red, 4 are yellow, 5 are green, and 3 are blue.

steposvetlana [31]

Answer:

3/16

Total no.of beads = 16

No.of blue beads = 3

Probability of picking a blue bead = 3/16

Step-by-step explanation:

Hope this helps

can i get braineist pls

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2 years ago

Pls help asap solve each inequality<br><br> 9n - 1 < 10n<br><br> 5h ≤ 12 + 4h

Stella [2.4K]

Here try this answer

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2 years ago

Read 2 more answers

f(x) = 0.2^x is transformed 9 units right, compressed vertically by a factor of 1/6 and reflected across the x-axis. Write the t

postnew [5]

Answer:

The function g(x) is defined as $g(x)=-\frac{1}{6}(0.2)^{x-9}$ .

Step-by-step explanation:

The given function is

$f(x)=-(0.2)^x$

The function f(x) transformed 9 units right, compressed vertically by factor of 1/6 and reflected across the x-axis.

The transformation of function is defined as

$g(x)=kf(x+b)+c$

Where, k is vertical stretch, b is horizontal shift and c is vertical shift.

If b>0, then the graph of f(x) shifts b units left and if b>0, then the graph of f(x) shifts b units right.

If c>0, then the graph of f(x) shifts c units upward and if c>0, then the graph of f(x) shifts c units downward.

The value of b is -9 because the graph shifts 9 units right. The value of k is 1/6. If the graph of function f(x)reflect across x-axis, therefore the function is defined as -f(x).

$g(x)=\frac{1}{6}(-f(x-9))$

$g(x)=-\frac{1}{6}(0.2)^{x-9}$ $[\because f(x)=-(0.2)^x]$

Therefore the function g(x) is defined as $g(x)=-\frac{1}{6}(0.2)^{x-9}$ .

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3 years ago

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